In physics, power is the rate of doing work. It is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. In the SI system, the unit of power is the joule per second (J/s), known as the watt in honour of James Watt, the eighteenth-century developer of the steam engine.
Answer:
the Molar heat of Combustion of diphenylacetylene
= ![-6.931 *10^3 \ kJ/mol](https://tex.z-dn.net/?f=-6.931%20%2A10%5E3%20%5C%20kJ%2Fmol)
Explanation:
Given that:
mass of diphenylacetylene
= 0.5297 g
Molar Mass of diphenylacetylene
= 178.21 g/mol
Then number of moles of diphenylacetylene
= ![\frac{mass}{molar \ mass}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bmolar%20%5C%20mass%7D)
= ![\frac{0.5297 \ g }{178.24 \ g/mol}](https://tex.z-dn.net/?f=%5Cfrac%7B0.5297%20%20%5C%20g%20%7D%7B178.24%20%5C%20%20g%2Fmol%7D)
= 0.002972 mol
By applying the law of calorimeter;
Heat liberated by 0.002972 mole of diphenylacetylene
= Heat absorbed by
+ Heat absorbed by the calorimeter
Heat liberated by 0.002972 mole of diphenylacetylene
= msΔT + cΔT
= 1369 g × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C
= 17756.48 J + 2842.39 J
= 20598.87 J
Heat liberated by 0.002972 mole of diphenylacetylene
= 20598.87 J
Heat liberated by 1 mole of diphenylacetylene
will be = ![\frac{20598.87 \ J}{0.002972 \ mol}](https://tex.z-dn.net/?f=%5Cfrac%7B20598.87%20%5C%20J%7D%7B0.002972%20%5C%20mol%7D)
= 6930979.139 J/mol
= 6930.98 kJ/mol
Since heat is liberated ; Then, the Molar heat of Combustion of diphenylacetylene
= ![-6.931 *10^3 \ kJ/mol](https://tex.z-dn.net/?f=-6.931%20%2A10%5E3%20%5C%20kJ%2Fmol)
Answer:
Gas
Explanation:
This is kind of like the process of evaporating
<span>6.38x10^-2 moles
First, let's determine how many moles of gas particles are in the two-liter container. The molar volume for 1 mole at 25C and 1 atmosphere is 24.465 liters/mole. So
2 L / 24.465 L/mol = 0.081749438 mol
Now air doesn't just consist of nitrogen. It also has oxygen, carbon dioxide, argon, water vapor, etc. and the total number of moles includes all of those other gasses. So let's multiply by the percentage of nitrogen in the atmosphere which is 78%
0.081749438 mol * 0.78 = 0.063764562 mol.
Rounding to 3 significant figures gives 6.38x10^-2 moles</span>