Answer:
Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]
Explanation:
Let's consider the dissociation reaction of the complex ion Ag(NH₃)₂⁺.
Ag(NH₃)₂⁺(aq) ⇄ Ag⁺(aq) + 2 NH₃(aq)
The dissociation constant, Kd, is the equilibrium constant for the dissociation of the complex ion, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.
The dissociation constant for this reaction is:
Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]
Answer:
17
Explanation:
Step 1: Calculate the needed concentrations
[A]i = 1.00 mol/5.00 L = 0.200 M
[B]i = 1.80 mol/5.00 L = 0.360 M
[B]e = 1.00 mol/5.00 L = 0.200 M
Step 2: Make an ICE chart
A(aq) + 2 B(aq) ⇄ C(aq)
I 0.200 0.360 0
C -x -2x +x
E 0.200-x 0.360-2x x
Then,
[B]e = 0.360-2x = 0.200
x = 0.0800
The concentrations at equilibrium are:
[A]e = 0.200-0.0800 = 0.120 M
[B]e = 0.200 M
[C]e = 0.0800 M
Step 3: Calculate the concentration equilibrium constant (K)
K = [C] / [A] × [B]²
K = 0.0800 / 0.120 × 0.200² = 16.6 ≈ 17
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Answer:
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Explanation:
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Answer:
cellular respiration. C6H12O6 + 6O2 → 6CO2 + 6H2O.
Explanation:
the process where cells convert chemical energy and/or nutrients into ATP and then the cells release the waste.
