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tekilochka [14]
2 years ago
10

What is the difference between test tube and boiling tube​

Chemistry
1 answer:
mixer [17]2 years ago
5 0

Test tubes heat small amounts of liquids while boiling tube boils liquids

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I need you to solve for me plzzzzzz
Sergeu [11.5K]

Answer:

.0556 L

Explanation:

First, convert the 1.35 M to 1.35 mol/L in order for the units to correctly cancel out.

Then, multiply (0.0725 moles Na2CO3/1) times (L/ 1.35 mol).

Finally, the answer will be .0556 L.

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3 0
2 years ago
A 25.0 g piece of aluminum (which has a molar heat capacity of 24.03 J/mol°C) is heated to 86.4°C and dropped into a calorimeter
Ira Lisetskai [31]

Answer:

m H2O = 56 g

Explanation:

  • Q = mCΔT

∴ The heat ceded (-) by the Aluminum part is equal to the heat received (+) by the water:

⇒ - (mCΔT)Al = (mCΔT)H2O

∴ m Al = 25.0 g

∴ Mw Al = 26.981 g/mol

⇒ n Al = (25.0g)×(mol/26.981gAl) = 0.927 mol Al

⇒ Q Al = - (0.927 mol)(24.03 J/mol°C)(26.8 - 86.4)°C

⇒ Q Al = 1327.64 J

∴ mH2O = Q Al / ( C×ΔT) = 1327.64 J / (4.18 J/g.°C)(26.8 - 21.1)°C

⇒ mH2O = 55.722 g ≅ 56 g

5 0
3 years ago
glucose 6‑phosphate+H2O⟶glucose+Pi glucose 6‑phosphate+H2O⟶glucose+Pi K′eq1=270 K′eq1=270 ATP+glucose⟶ADP+glucose 6‑phosphate AT
ddd [48]

Answer:

-30.7 kj/mol

Explanation:

The standard free energy for the given reaction that is the hydrolysis of ATP is calculated using the formula:  ∆Go ’= -RTln K’eq

where,  

R = -8.315 J / mo

T = 298 K

For reaction,

1. K′eq1=270,

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 270

=  - 8.315 x 298 x 5.59

= - 13,851.293 J / mo

= - 13.85 kj/mol

2. K′eq2=890

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 890

=  - 8.315 x 298 x 6.79

=  - 16.82 kj/mol

therefore, total standard free energy

= - 13.85 + (-16.82)

=  -30.7 kj/mol

Thus, -30.7 kj/mol is the correct answer.

6 0
3 years ago
Si Units Worksheet. Use si units to complete
Keith_Richards [23]

\\ \bull\tt\dashrightarrow 2000m=2km

\\ \bull\tt\dashrightarrow 9000mL=9L

\\ \bull\tt\dashrightarrow 6L=6000mL

\\ \bull\tt\dashrightarrow 6cm=60mm

\\ \bull\tt\dashrightarrow 1000m=1km

\\ \bull\tt\dashrightarrow 50mm=5cm

\\ \bull\tt\dashrightarrow 4L=4000mL

\\ \bull\tt\dashrightarrow 10000g=10kg

\\ \bull\tt\dashrightarrow 10000m=10km

\\ \bull\tt\dashrightarrow 4000g=4kg

\\ \bull\tt\dashrightarrow 9km=9000m

\\ \bull\tt\dashrightarrow 3kg=3000g

\\ \bull\tt\dashrightarrow 90mm=9cm

\\ \bull\tt\dashrightarrow 4km=4000m

\\ \bull\tt\dashrightarrow 2000g=2kg

\\ \bull\tt\dashrightarrow 400cm=4m

\\ \bull\tt\dashrightarrow 3km=3000m

\\ \bull\tt\dashrightarrow 2cm=20mm

\\ \bull\tt\dashrightarrow 9000g=9kg

8 0
2 years ago
Describe how surface currents would be effective Earth did not rotate
kicyunya [14]
The moon is what makes currents so if there was no moon there would be no current in our oceans. The way it makes currents is from the gravitational pull.
Brainliest? :)
3 0
3 years ago
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