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2 years ago

What is the difference between test tube and boiling tube

Chemistry

1 answer:

mixer [17]2 years ago

5 0

Test tubes heat small amounts of liquids while boiling tube boils liquids

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Need help on B and C please!!

puteri [66]

B. The reason the temperature experienced no change in group c is because it was likely the control group.
I cannot read question c, the monitor refresh is obscuring the text.

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3 years ago

The downward force acting on an object in free fall is the force of

Eduardwww [97]

Gravittyyyyyyyyy ..........................
i was reported but the answer is gravity you can only be reporting if you offering 1000 points but if not please exit stage right

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3 years ago

Read 2 more answers

A thermometer having first-order dynamics with a time constant of 1 min is placed in a temperature bath at 100oF. After the ther

sveticcg [70]

Answer:

(a) See below

(b) 103.935 °F; 102.235 °F

Explanation:

The equation relating the temperature to time is

$T = T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )$

1. Calculate the thermometer readings after 0.5 min and 1 min

(a) After 0.5 min

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-0.5/1} \right )\\ & = & 100 + 10\left (1 - e^{-0.5} \right )\\ & = & 100 + 10 (1 - 0.6065)\\ & = & 100 + 10(0.3935)\\ & = & 100 + 3.935\\ & = & 103.935\,^{\circ}F\\\end{array}$

(b) After 1 min

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-1/1} \right )\\ & = & 100 + 10\left (1 - e^{-1} \right )\\ & = & 100 + 10 (1 - 0.3679)\\ & = & 100 + 10(0.6321)\\ & = & 100 + 6.321\\ & = & 106.321\,^{\circ}F\\\end{array}$

2. Calculate the thermometer reading after 2.0 min

T₀ =106.321 °F

ΔT = 100 - 106.321 °F = -6.321 °F

t = t - 1, because the cooling starts 1 min late

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-(t - 1)/\tau} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-(2 - 1)/1} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-1} \right )\\ & = & 106.321 - 6.321 (1 - 0.3679)\\ & = & 106.321 - 6.321 (0.6321)\\ & = & 106.321 - 3.996\\ & = & 102.325\,^{\circ}F\\\end{array}$

3. Plot the temperature readings as a function of time.

The graphs are shown below.

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3 years ago

In the Formula 3H2O what is the 3 called

vekshin1

Its very simple .

3H2O ---- three H two O

Its 3 molecules of water

3 0

3 years ago

Read 2 more answers

A thin metallic spherical shell of radius 41.6 cm has a total charge of 8.55 μC uniformly distributed on it. At the center of th

Paul [167]

Answer:

E = 1.2443*10⁶ N/C

Explanation:

R = 41.6 cm = 0.416 m

Q₁ = 8.55 μC = 8.55*10⁻⁶C

Q₀ = 4.43 μC = 4.43*10⁻⁶C

r = 17.9 cm = 0.179 m

K = 9*10⁹ N*m²/C²

Since r < R we can apply Gauss's Law as follows

E = K*Q₀ / r²

⇒ E = (9*10⁹ N*m²/C²)*(4.43*10⁻⁶C) / (0.179 m)²

⇒ E = 1.2443*10⁶ N/C

5 0

3 years ago

What is the difference between test tube and boiling tube​

What is the difference between test tube and boiling tube