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Kaylis [27]
3 years ago
14

What is the ph of a solution with a hydroxyl ion (oh-) concentration of 10-10 m? what is the ph of a solution with a hydroxyl io

n (oh-) concentration of 10-10 m? ph 10 ph 12 ph 4 ph 2?
Chemistry
2 answers:
loris [4]3 years ago
7 0
PH is the potential of hydrogen. 
pH = -log₁₀(H+) 
while, pOH = -log₁₀(OH-)
But; pH + pOH =14
Therefore; for a solution with a concentration of (OH-) of 10^-10
The pOH= -log(10^-10)
              = 10 
Therefore pH =14-10
                      = 4
krek1111 [17]3 years ago
3 0
According to this formula:
pH = - log [H]
And, pOH = - log [OH] >>> (1)
Where, pH + pOH = 14  >>> (2)
∵ the hydroxide ion concentration = (OH-) = 10 ^ -10 M
from (1) and (2) and by substitution: 
∴ pOH = - log [10^-10] = 10 
∴ pH = 14 - 10 = 4 
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Answer:

0.0468 g.

Explanation:

  • The decay of radioactive elements obeys first-order kinetics.
  • For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).

Where, k is the rate constant of the reaction.

t1/2 is the half-life time of the reaction (t1/2 = 1620 years).

∴ k = ln2/(t1/2) = 0.693/(1620 years) = 4.28 x 10⁻⁴ year⁻¹.

  • For first-order reaction: <em>kt = lna/(a-x).</em>

where, k is the rate constant of the reaction (k = 4.28 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = t1/2 x 8 = 1620 years x 8 = 12960 year).

a is the initial concentration (a = 12.0 g).

(a-x) is the remaining concentration.

∴ kt = lna/(a-x)

(4.28 x 10⁻⁴ year⁻¹)(12960 year) = ln(12)/(a-x).

5.54688 = ln(12)/(a-x).

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256.34 = (12)/(a-x).

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The time period t of a beam of light is the same as the time between two consecutive peaks. If \lambda is the wavelength of the beam, and both the source and observer are static, the time period T will be the same as the time it takes for light travel the distance of one \lambda (at the speed of light in vacuum, c).

\displaystyle t = \frac{\lambda}{c}.

Frequency f is the reciprocal of time period. Therefore

\displaystyle f = \frac{1}{t} = \frac{c}{\lambda}.

Light travels in vacuum at a constant speed. However, in a collapsing universe, the star that emit the light keeps moving towards the observer. Let the distance between the star and the observer be d when the star sent the first peak.

  • Distance from the star when the first peak is sent: d.
  • Time taken for the first peak to arrive: \displaystyle t_1 =\frac{d}{c}.

The star will emit its second peak after a time of. Meanwhile, the distance between the star and the observer keeps decreasing. Let v be the speed at which the star approaches the observer. The star will travel a distance of v\cdot t before sending the second peak.

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The period of the light is t when emitted from the star. However, the period will appear to be shorter than t for the observer. The time period will appear to be:

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When the universe collapses, one possibility is that clusters of stars move towards each other. Alternatively, the space fabric might shrink, which will also bring the clusters toward each other.

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Colors at the short-wavelength end of the visible spectrum are blue and violet. Again, the color of the light will shift towards the blue end of the spectrum. The conclusion will be the same: a collapsing universe will cause a blueshift on light from distant stars.

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5) They all involve an interaction between living and nonliving elements.

6)They are all part of the Earth system.

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