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Kaylis [27]
3 years ago
14

What is the ph of a solution with a hydroxyl ion (oh-) concentration of 10-10 m? what is the ph of a solution with a hydroxyl io

n (oh-) concentration of 10-10 m? ph 10 ph 12 ph 4 ph 2?
Chemistry
2 answers:
loris [4]3 years ago
7 0
PH is the potential of hydrogen. 
pH = -log₁₀(H+) 
while, pOH = -log₁₀(OH-)
But; pH + pOH =14
Therefore; for a solution with a concentration of (OH-) of 10^-10
The pOH= -log(10^-10)
              = 10 
Therefore pH =14-10
                      = 4
krek1111 [17]3 years ago
3 0
According to this formula:
pH = - log [H]
And, pOH = - log [OH] >>> (1)
Where, pH + pOH = 14  >>> (2)
∵ the hydroxide ion concentration = (OH-) = 10 ^ -10 M
from (1) and (2) and by substitution: 
∴ pOH = - log [10^-10] = 10 
∴ pH = 14 - 10 = 4 
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Determine which law is appropriate for solving the following problem. Carbon dioxide is in a steel tank at 20°C, 10 liters and 1
patriot [66]

<u>Answer:</u>

Law used: Combined Gas Law

<u>Explanation:</u>

We are given the following problem:

Carbon dioxide is in a steel tank at 20°C, 10 liters and 1 atm. What is the pressure on the gas when the tank is heated to 100°C?

To solve this, the most appropriate law that can be used it Combined Gas Law, which is the result of combining the Boyle's law, Charles' law, and Gay-Lussac's law together.

5 0
3 years ago
Read 2 more answers
draw the organic product formed when 1−hexyne is treated with h2o, h2so4, and hgso4. click the draw structure button to launch t
V125BC [204]

The organic product formed when 1−hexyne is treated with H₂O, H₂SO₄, and HgSO₄ will be 2-hexanone (structure attached).

This reaction is an example of an oxymercuration reaction of the organic product 1−hexyne.

Oxymercuration is shown in three steps to the right. The nucleophilic double bond attacks the mercury ion, releasing an acetoxy group. The mercury ion's electron pair attacks carbon on the double bond, generating a positive-charged mercuronium ion. Mercury's dxz and 6s orbitals give electrons to the double bond's lowest unoccupied molecular orbitals.

In the second stage, the nucleophilic H₂O attacks the highly modified carbon, freeing its mercury-bonding electrons. Electrons neutralize mercury ions by collapsing. Water molecules have positive-charged oxygen.

In the third stage, the negatively charged acetoxy ion released in the first step attacks the hydrogen of the water group, generating the waste product HOAc. The two electrons in the oxygen-hydrogen link collapse into oxygen, neutralizing its charge and forming alcohol.

You can also learn about organic products from the following question:

brainly.com/question/13513481

#SPJ4

4 0
1 year ago
How many atoms are present in 34.69 moles of Mg
shusha [124]
<span>Avogadro's number. 

1 mole of any substance, molecule or element is equal to a certain amount of atom. 

6.022 x 10^23 is the Avogradro's constant. 

Magnesium Oxide is a compound. therefore if you have 30.3 g of it (1 mol), it will have the same number of atoms. 

34.69 moles of MgO has 208.9 x 10^23 number of atoms. 

2.089 x 10^25 is also a correct answer.</span><span>
</span>
7 0
3 years ago
Question 2 of 50
wolverine [178]

The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.

Further Explanation:

To solve this problem, follow the steps below:

  1. Write the balanced chemical equation for the given reaction.
  2. Convert the mass of calcium carbonate into moles.
  3. Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
  4. Convert the number of moles of calcium oxide into mass.

Solving the given problem using the steps above:

STEP 1: The balanced chemical equation for the given reaction is:

CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.

For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

mol \ CaO \ = 0.2498 \ mol

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.

Therefore,

\boxed {mass \ CaO \ = 14 \ g}

Learn More

  1. Learn more about stoichiometry brainly.com/question/12979299
  2. Learn more about mole conversion brainly.com/question/12972204
  3. Learn more about limiting reactants brainly.com/question/12979491

Keywords: thermal decomposition, stoichiometry

5 0
3 years ago
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