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ycow [4]
3 years ago
6

Nicolaus Copernicus was a Polish astronomer who is best known for the theory that the sun is near the center of the universe and

that the earth and other planets revolve around it. Copernicus did not believe that the planets were influenced by or revolved due to the sun; instead he believed that the sun was located near the center of the universe and that it was this center which influenced those bodies and caused them to revolve. When this theory was first published, the scientific community did not accept it. Which reason BEST explains the reason for rejection of this theory? A) It was not published until his death. B) It was not understood by scientific world. C) It lacked sufficient evidence and explanation. D) It lacked practical examples in supporting theory.
Physics
1 answer:
serg [7]3 years ago
3 0

Answer:

DOUBLE CHECK BECUASE IM ONLY 68.030303039999999% SURE!!!

(ANSWER IS HERE)    ( D) It lacked practical examples in supporting theory

Know it's not B becuase there was no scientific community back then.

Know it's not C becuase it actully had lots of evidence.

But I'm not sure about A

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Which lists the evidense to varify a chemical change occurred instaed of a phicical change
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Explanation:

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An emf is induced in response to a change in magnetic field inside a loop of wire. Which of the following changes would increase
goldenfox [79]

Answer:

changing the magnetic field more rapidly

Explanation:

According to Faraday's law, whenever there is a change in the magnetic lines of force, it leads the production of induced emf. The magnitude of induced emf is proportional to to the rate of change of flux.

Hence if the magnetic field inside a loop of wire is changed rapidly, the magnitude of induced emf increases in accordance with Faraday's law of electromagnetic induction stated above when the magnetic field is changed more rapidly, hence the answer.

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What do the top of a zip line and the top of a bungee cord have in common
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2 years ago
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A capacitor is connected across an ac source. Suppose the frequency of the source is doubled. What happens to the capacitive rea
fgiga [73]

The capacitive reactance is reduced by a factor of 2.

<h3>Calculation:</h3>

We know the capacitive reactance is given as,

Xc = \frac{1}{2\pi fC}

where,

Xc\\ = capacitive reactance

f = frequency

C = capacitance

It is given that frequency is doubled, i.e.,

f' = 2f

To find,

Xc =?

Xc' = \frac{1}{2\pi f'C}

      = \frac{1}{2\pi 2f C}

      = \frac{1}{2} (\frac{1}{2\pi fC} )\\

Xc' = \frac{1}{2} Xc

Therefore, the capacitive reactance is reduced by a factor of 2.

I understand the question you are looking for is this:

A capacitor is connected across an AC source. Suppose the frequency of the source is doubled. What happens to the capacitive reactant of the inductor?

  1. The capacitive reactance is doubled.
  2. The capacitive reactance is traduced by a factor of 4.
  3. The capacitive reactance remains constant.
  4. The capacitive reactance is quadrupled.
  5. The capacitive reactance is reduced by a factor of 2.

Learn more about capacitive reactance here:

brainly.com/question/23427243

#SPJ4

3 0
2 years ago
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