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4 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics

2 answers:

Schach [20]4 years ago

8 0

D. To express percent error

aev [14]4 years ago

5 0

A. To express large and small numbers

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square root A 1400 kg car is coasting on a horizontal road with a speed of 18 m/s . After passing over an unpaved, sandy stretch

Lina20 [59]

Answer:

The net force on the car is 2560 N.

Explanation:

According to work energy theorem, the amount of work done is equal to the change of kinetic energy by an object. If ' $W$ ' be the work done on an object to change its kinetic energy from an initial value ' $K_{i}$ ' to the final value ' $K_{f}$ ', then mathematically,

$W = K_{f} - K_{i} = \dfrac{1}{2}~m~(v_{f}^{2} - v_{i}^{2})........................................(I)$

where ' $m$ ' is the mass of the object and ' $v_{i}$ ' and ' $v_{f}$ ' be the initial and final velocity of the object respectively. If ' $F_{net}$ ' be the net force applied on the car, as per given problem, and ' $s$ ' is the displacement occurs then we can write,

$W = F_{net}~.~s.......................................................(II)$

Given, $m = 1400~Kg,~v_{i} = 18~m~s^{-1}~v_{f} = 14~m~s^{-1}~and~s = 35~m$ .

Equating equations (I) and (II),

$&& - F_{net} \times 35~m = \dfrac{1}{2} \times 1400~Kg~\times(14^{2} - 18^{2})~m^{2}~s^{-2}\\&or,& F_{net} = \dfrac{\dfrac{1}{2} \times 1400~Kg~\times(14^{2} - 18^{2})}{35}~N\\&or,& F_{net} = 2560~N$

6 0

3 years ago

A piece of warm concrete is placed in a cold-water tank, and energy flows between the concrete and the water. Which way does the

sammy [17]

Answer:

Heat flows from hot to cold objects. When a hot and a cold body are in thermal contact, they exchange heat energy until they reach thermal equilibrium, with the hot body cooling down and the cold body warming up. This is a natural phenomenon we experience all the time.

Explanation:

3 0

2 years ago

What is the density of a 15 g box measuring<br> 10 cm hy 5 cm by 2 cm?

Dvinal [7]

Answer:

The density of the box is 0.15 g/cm³

Explanation:

Given;

mass of the box, m = 15 g

dimension of the box, = 10 cm by 5 cm by 2 cm

Volume of the box, v = 10 cm x 5 cm x 2 cm = 100 cm³

The density of the box is given by;

Density = mass / volume

Density = 15 g / 100 cm³

Density = 0.15 g/cm³

Therefore, the density of the box is 0.15 g/cm³

8 0

4 years ago

4720 kj of energy are supplied to a material in order to raise its temperature by 65k. if the specific heat capacity of the mate

jeka57 [31]

The mass of material is 26.6 Kg

Given:

Q = 4720 KJ

Change in Temperature (AT) = 65 K

Specific heat capacity of material (c) = 2730 J K Kg*K

The relation between Q, AT, c and m are related by following formula: Q=m* c*∆T,

Plugging value in heat formula:

4720KJ = m* 2730 J/Kg*K * 65K

4720KJ = m * 177450J/kg

Converting 177450 J/kg to Kg/KJ

177450 J/kg*1KJ/1000J = 177.450KJ/kg

Dividing both side by 177.450KJ/kg

4720KJ/177.450KJ/Kg = m*177.450KJ/Kg÷ 177.450KJ/Kg

Hence, the mass of material = 26.6 Kg

Learn more about Mass here:

brainly.com/question/19385703

#SPJ4

6 0

2 years ago

Can God make a rock that He can't carry?

Xelga [282]

Answer:

The answer to the question lies in the character of God. God is either finite or infinite. If God is finite and limited, then God could make a rock He could not lift. If God is unlimited in power, then He could create a rock of any size and weight and still be able to lift it.

Explanation:

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2 years ago