Answer:
Speed of the wave is 7.87 m/s.
Explanation:
It is given that, tapping the surface of a pan of water generates 17.5 waves per second.
We know that the number of waves per second is called the frequency of a wave.
So, f = 17.5 Hz
Wavelength of each wave, 
Speed of the wave is given by :
v = 7.87 m/s
So, the speed of the wave is 7.87 m/s. Hence, this is the required solution.
<span>-- the product of the net charges on the objects;. -- the distance between the centers of their net charges. (Pretty much identical to the formula for gravitational force)</span>
<span>7.7 m/s
First, determine the acceleration you subject the sled to. You have a mass of 15 kg being subjected to a force of 180 N, so
180 N / 15 kg = 180 (kg m)/s^2 / 15 kg = 12 m/s^2
Now determine how long you pushed it. For constant acceleration the equation is
d = 0.5 A T^2
Substitute the known values getting,
2.5 m = 0.5 12 m/s^2 T^2
2.5 m = 6 m/s^2 T^2
Solve for T
2.5 m = 6 m/s^2 T^2
0.41667 s^2 = T^2
0.645497224 s = T
Now to get the velocity, multiply the time by the acceleration, giving
0.645497224 s * 12 m/s^2 = 7.745966692 m/s
After rounding to 2 significant figures, you get 7.7 m/s</span>
The glowing beam was repelled by a negatively charged plate because they were negatively charged
<h3>What are the nature of charges?</h3>
The nature of charges refers to the properties of charges.
There are two types of charges:
- negative charges
- positive charges
The law of electricity states that opposite charges attract whereas like charges repel.
Therefor, in Thomson’s experiment, the glowing beam was repelled by a negatively charged plate because they were negatively charged
In conclusion, like charges repel while opposite charges attract.
Learn more about charges at: brainly.com/question/12781208
#SPJ1
Explanation:
Crust...molten
a. Oceanic, iron
b. Continental, silicates
c. less
3. Mantle, Denser
a. Lithosphere
b. Asthenosphere
4. Core
a. elements, rocks
b. liquid, magnetic
(I guess the liquid should come after the is)
Couldn't answer all but wanted to help
