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3 years ago

5

Who wants to throw a sleepover please comment and I’ll give the fun school and sleepover room!! Plus I need help with a assignme

nt. I’ll ask it in the room.

1 answer:

solniwko [45]3 years ago

5 0

Answer:

Hi usiwiwuwgwhwia I will lop

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g (12 points) The time between incoming phone calls at a call center is a random variable with exponential density p(x) = 1 r e

rusak2 [61]

Answer:

$(1)p(x)\geq 0\\(2)\int_{0}^{\infty} p(x) dx=0$

Explanation:

A function f(x) is a Probability Density Function if it satisfies the following conditions:

$(1)f(x)\geq 0\\(2)\int_{0}^{\infty} f(x) dx=0$

Given the function:

$p(x)=\dfrac{1}{r}e^{-x/r} \: on\: [0,\infty), where\:r=\dfrac{20}{ln(2)}$

(1)p(x) is greater than zero since the range of exponents of the Euler's number will lie in $[0,\infty).$

(2)

$\int_{0}^{\infty} p(x)=\int_{0}^{\infty} \dfrac{1}{r}e^{-x/r}\\=\dfrac{1}{r} \int_{0}^{\infty} e^{-x/r}\\=-\dfrac{r}{r}\left[e^{-x/r}\right]_{0}^{\infty}\\=-\left[e^{-\infty/r}-e^{-0/r}\right]\\=-e^{-\infty}+e^{-0}\\SInce \: e^{-\infty} \rightarrow 0\\e^{-0}=1\\\int_{0}^{\infty} p(x)=1$

The function p(x) satisfies the conditions for a probability density function.

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3 years ago

Scheduling comes before sequencing. In scheduling, we develop plans for our work centers where production activities occur. We l

ser-zykov [4K]

Answer: 89

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An example of a folkway violation would be driving 70 mph in a 50-mph zone. Group of answer choices True False

shutvik [7]

Answer:

Yes.

Explanation:

That is also a law violation.

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The radius of the wheel is 40cm and the radius of the

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Answer:

M.A = load/ effort

1200N/400N

= 3

velocity ratio= radius of wheel/radius of Axle

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efficiency= 3/4*100

75%

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plz write your questions in English

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