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3 years ago

What do you need to build a working electric motor?

Physics

1 answer:

FrozenT [24]3 years ago

5 0

Answer: <u><em>D a source of electricity</em></u>

Explanation: I have done that question please tell me if it is correct

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A small spaceship whose mass is 1300 kg (including an astronaut) is drifting in outer space with negligible gravitational forces

Alexxandr [17]

Answer:

Explanation:

Relation between energy and momentum is as follows .

E = h c / λ

E / c = h / λ

h /λ = momentum of a photon

momentum of a photon = E /c

= 11 x 10³ / 3 x 10⁸

= 3.67 x 10⁻⁵

In 4 days no of photon

= 4 x 24 x 60 x 60 = 345600 .

momentum of photon released

3.67 x 10⁻⁵ x 345600 .

= 12.68 kg m/s

This momentum will be imparted to spaceship .

12.68 = mv

12 .68 = 1300 x v

v = .00975 m /s

= 9.75 mm /s

8 0

3 years ago

A trolley of mass 4 kg moves with a velocity of 0.5 meter per second It colides with a stationary trolley of mass 3 kg. If the t

Luda [366]

Answer:

Approximately $0.29\; {\rm m \cdot s^{-1}}$ .

Explanation:

Make use of the fact that total momentum is conserved in collisions.

The momentum of an object of mass $m$ and velocity $v$ is $p = m\, v$ .

The momentum of the two trolleys before the collision would be:

$4\; {\rm kg} \times 0.5\; {\rm m \cdot s^{-1}} = 2\; {\rm kg \cdot m \cdot s^{-1}}$ .
$3\; {\rm kg} \times 0\; {\rm m\cdot s^{-1}} = 0\; {\rm kg \cdot m \cdot s^{-1}}$ .

Thus, the total momentum of the two trolleys right before the collision would be $2\; {\rm kg \cdot m \cdot s^{-1}}$ .

Since the two trolleys are stuck to one another after the collision, they could modelled as one big trolley of mass $m = 3\; {\rm kg} + 4\; {\rm kg} = 7\; {\rm kg}$ .

The momentum of the two trolleys, combined, is conserved during the collision. Thus, the total momentum of the new trolley of mass $m = 7\; {\rm kg}$ would continue to be $v = 2\; {\rm kg \cdot m \cdot s^{-1}}$ shortly after the collision.

Rearrange the equation $p = m\, v$ to find the velocity of the two trolleys combined:

$\begin{aligned}v &= \frac{p}{m} \\ &= \frac{2\; {\rm kg \cdot m \cdot s^{-1}}}{7\; {\rm kg}} \\ &\approx 0.29\; {\rm m \cdot s^{-1}}\end{aligned}$ .

6 0

2 years ago

The magnitude of the action potential is correlated with the strength of the stimulating input. True or False

Vesnalui [34]

Answer:

True

Explanation:

3 0

3 years ago

A(n) 69.8 kg astronaut becomes separated from the shuttle, while on a space walk. She finds herself 60.4 m away from the shuttle

alukav5142 [94]

Answer:

The time taken is 6.7 min

Explanation:

Using the linear momentum conservation theorem, we have:

$m_1*v_{o1}+m_2*v_{o2}=m_1*v_{f1}+m_2*v_{f2}$

when she was 60.4m from the shuttle, she has zero speed, so the initial velocity is zero.

$m_1*0+m_2*0=m_1*v_{f1}+m_2*v_{f2}\\m_1*_{f1}=-m_2*v_{f2}\\v_{f1}=-\frac{m_2*v_{f2}}{m_1}\\\\v_{f1}=-\frac{0.886kg*12m/s}{69.8kg}\\\\V_{f1}=-0.15m/s$

That is 0.15m/s in the opposite direction of the camera.

the time taken to get to the shuttle is given by:

$t=\frac{d}{v_{f1}}\\\\t=\frac{60.4m}{0.15m/s}\\\\t=403s\\t_{min}=403s*\frac{1min}{60s}=6.7min$

6 0

3 years ago

i need the answer asap plz A child rides her bike at a rate of 12.0 km/hr down the street. A squirrel suddenly runs in front of

Kruka [31]

-16 km/hr/sec because she slows down 4 km/hr (12 - 8) in 0.25 seconds. in one second (0.25 sec * 4) she would slow down by 16 km/hr (4 * 4). it’s negative acceleration because she’s slowing down

5 0

3 years ago

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