A ball is thrown horizontally at a speed of 16 m/s from the top of a cliff. If the ball hits the ground 6.0 s later, approximate
1 answer:
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The gravitational force between the two objects A) It increases.
Explanation:
The gravitational force between two objects is given by:
(1)
where
G is the gravitational constant
are the masses of the two objects
r is the separation between the objects
In this problem, object A and object B are initially at a distance of
r = 100 m
And at that distance, the force between them is
F
Later, object A gains some mass. We notice from eq.(1) that the gravitational force is directly proportional to the mass: therefore, if the mass of either of the two objects increases, then the gravitational force between them also increases. Therefore, the new force will be larger than the original force:
F' > F
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Answer:
4.167
4.83871 cm
Explanation:
u = Object distance
v = Image distance = 25 cm
f = Focal length = 6 cm
Angular magnification is given by
The angular magnification of the lens is 4.167
Lens equation
The closest distance by which the object can be examined is 4.83871 cm
We need to find the average speed of the ball during the motion of 1 m
In order to find that we took several reading and found following times to cover the distance of 1 m
t1 = 2.26 s
t2 = 2.38 s
t3 = 3.02 s
t4 = 2.26 s
t5 = 2.31 s
Now in order to find the average time we can write
So average time to cover the distance of 1 m by ball will be 2.45 s
here 3.02 s is not the average time but we can say it is the median of the readings of all possible values which we can not use in our calculation as average time