Answer:
Total mass of combination = 2+3+5 = 10kg.
Acceleration produced = 2m/s^2
hence force =( total mass × acceleration)= (2×10)= 20 N.
Net force on 3kg block = acceleration × mass = (2 × 2 )= 4 N
applied force on 2 kg block = 20N
Force between 2 kg and 3 kg block = (20-4) = 16N. ans
Net force on 3 kg block = 3 × 2 =6N.
Applied force on 3 kg block due to 2 kg block = 16N.
hence, force between 3 kg and 5 kg block = (16-6) = 10N .
answers:-
(a) 20 N
(b) 16N
(c) 10 N
Answer:
550000000N/m
Explanation:
Given that a copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends of the wire, the wire stretches by 5.0×10−3 of its original length.
Original length L = 0.005L
the strain = extension/ original length
the strain = 0.005L / L
the strain = 0.005
Young modulus = stress / strain
11 × 10^10 = stress / 0.005
Cross multiply
Stress = 11 × 10^10 × 0.005
Stress = 550 000000 N/m
Therefore, the tensile stress on the wire is 550000000 N/m.
Answer:
Idk I think we all ask the question also this question is for sure prob getting deleted just saying now not by me
Explanation:
The answer is C. 8.0
Factor in the resistors and take into account the 4.0 W connection. Then do it like you normally would with the 4.0 W included. This will give you 8.0, simple :)
Hope this helped. Have a great day!
In this case, the PWC will head for the dock. This is because, power needs to be applied in order to maintain steering control. If the throttle is left to idle or if the engine is turn off during operation, all steering control will be lost. In each of this situation, the PWC will continue in the was headed before the engine was turned off or before the throttle was left to idle.
