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galben [10]
3 years ago
12

Restrictive covenants are designed to protect both the bondholder and the issuer even though they might constrain the actions of

the firm's managers. Such covenants are contained in the bond's indenture. a. True b. False
Chemistry
1 answer:
Ostrovityanka [42]3 years ago
6 0

Answer:

The answer is True

Explanation:

This is true because it is designed to protect the interest of the bond holder and the bond issuer.

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A 1.93-mol sample of xenon gas is maintained in a 0.805-L container at 306 K. Calculate the pressure of the gas using both the i
Alex

Answer : The pressure of the gas using both the ideal gas law and the van der Waals equation is, 60.2 atm and 44.6 atm respectively.

Explanation :

First we have to calculate the pressure of gas by using ideal gas equation.

PV=nRT

where,

P = Pressure of Xe gas = ?

V = Volume of Xe gas = 0.805 L

n = number of moles Xe = 1.93 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of Xe gas = 306 K

Now put all the given values in above equation, we get:

P\times 0.805L=1.93mole\times (0.0821L.atm/mol.K)\times 306K

P=60.2atm

Now we have to calculate the pressure of gas by using van der Waals equation.

(P+\frac{an^2}{V^2})(V-nb)=nRT

P = Pressure of Xe gas = ?

V = Volume of Xe gas = 0.805 L

n = number of moles Xe = 1.93 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of Xe gas = 306 K

a = pressure constant = 4.19L^2atm/mol^2

b = volume constant = 5.11\times 10^{-2}L/mol

Now put all the given values in above equation, we get:

(P+\frac{(4.19L^2atm/mol^2)\times (1.93mole)^2}{(0.805L)^2})[0.805L-(1.93mole)\times (5.11\times 10^{-2}L/mol)]=1.93mole\times (0.0821L.atm/mol.K)\times 306K

P=44.6atm

Therefore, the pressure of the gas using both the ideal gas law and the van der Waals equation is, 60.2 atm and 44.6 atm respectively.

5 0
3 years ago
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