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3 years ago

How many electrons will a metal generally have in its outer energy level?

Chemistry

1 answer:

Zarrin [17]3 years ago

4 0

Answer:

Metals have one or two electrons in their outermost shell

C. 1-2

Explanation:

Metals have low ionisation energy because they easily looses the outermost electrons

They have only one- two electrons in the outer most shell.

They loose these electron to form charged species called cation.

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Goodyear tires are listed with 29.72 psi pressure limits in the summer, with 10.22 L of air. In the winter, however, the volume

serg [7]

Answer:

42.24 psi.

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 29.72 psi

Initial volume (V₁) = 10.22 L

Final volume (V₂) = 7.19 L

Final pressure (P₂) =?

The final pressure can be obtained by applying the Boyle's law equation as follow:

P₁V₁ = P₂V₂

29.72 × 10.22 = P₂ × 7.19

303.7384 = P₂ × 7.19

Divide both side by 7.19

P₂ = 303.7384 / 7.19

P₂ = 42.24 psi

Therefore, the final pressure is 42.24 psi

6 0

3 years ago

Elements with atomic numbers 7 and 83 have how many valence electrons? *

IRINA_888 [86]

Explanation:

element with atomic numbers 7 and 83 have 5 and 5 valence electrons

5 0

3 years ago

Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . Calculate t

Sedbober [7]

Answer:

Approximately $6.30\times 10^{-3}\;\rm mol$ .

Explanation:

The gallium here is likely to be produced from a $\rm NaGaO_2\, (aq)$ solution using electrolysis. However, the problem did not provide a chemical equation for that process. How many electrons will it take to produce one mole of gallium?

Note the Roman Numeral " $\mathtt{(III)}$ " next to $\rm Ga$ . This numeral indicates that the oxidation state of the gallium in this solution is equal to $+3$ . In other words, each gallium atom is three electrons short from being neutral. It would take three electrons to reduce one of these atoms to its neutral, metallic state in the form of $\rm Ga\, (s)$ .

As a result, it would take three moles of electrons to deposit one mole of gallium atoms from this gallium $\mathtt{(III)}$ solution.

How many electrons are supplied? Start by finding the charge on all the electrons in the unit coulomb. Make sure all values are in their standard units.

$t = \rm 80.0\; min = 80.0\; min \times 60\;s \cdot min^{-1} = 4800\; s$ .

$Q = I \cdot t = \rm 0.380 \; A \times 4800 \; s = 1.824\times 10^3\; C$ .

Calculate the number of electrons in moles using the Faraday's constant. This constant gives the size of the charge (in coulombs) on each mole of electrons.

$\begin{aligned} n(\text{electrons}) &= \frac{Q}{F} \cr &= \rm \dfrac{1.824\times 10^3\; C}{96485.332\; C \cdot mol^{-1}}\cr &\approx \rm 1.89\times 10^{-2}\; mol \end{aligned}$ .

It takes three moles of electrons to deposit one mole of gallium atoms $\rm Ga\, (s)$ . As a result, $\rm 1.89\times 10^{-2}\; mol$ of electrons would deposit $\displaystyle \rm \frac{1}{3}\times 1.89\times 10^{-2}\; mol \approx 6.30\times 10^{-3}\; mol$ of gallium atoms $\rm Ga\, (s)$ .