Answer:
it's pray hoped this helped
Answer:
<em>Velocity</em><em> </em><em>-</em><em>time</em><em> </em><em>graph</em><em> </em>
Explanation:
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Answer:
– 2.5 m/s²
Explanation:
We have,
• Initial velocity, u = 180 km/h = 50 m/s
• Final velocity, v = 0 m/s (it stops)
• Time taken, t = 20 seconds
We have to find acceleration, a.
a = (v ― u)/t
a = (0 – 50)/20 m/s²
a = –50/20 m/s²
a = – 5/2 m/s²
a = – 2.5 m/s² (Velocity is decreasing) [Answer]
<u>Answer:</u> The elevation in boiling point is 1.024°C.
<u>Explanation:</u>
To calculate the elevation in boiling point, we use the equation:
![\Delta T_b=ik_b\times m](https://tex.z-dn.net/?f=%5CDelta%20T_b%3Dik_b%5Ctimes%20m)
where,
i = Van't Hoff factor = 2 (for NaCl)
= change in boiling point = ?
= boiling point constant = ![0.512^oC/m](https://tex.z-dn.net/?f=0.512%5EoC%2Fm)
m = molality = 1.0 m
Putting values in above equation, we get:
![\Delta Tb=2\times 0.512^oC/m\times 1.0m\\\\\Delta Tb=1.024^oC](https://tex.z-dn.net/?f=%5CDelta%20Tb%3D2%5Ctimes%200.512%5EoC%2Fm%5Ctimes%201.0m%5C%5C%5C%5C%5CDelta%20Tb%3D1.024%5EoC)
Hence, the elevation in boiling point is 1.024°C.