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DerKrebs [107]
2 years ago
14

What best describes a possible transfer of energy? A mechanical wave transfers energy through matter. A longitudinal wave transf

ers energy perpendicular to wave motion. A transverse wave transfers energy parallel to wave motion. A sound wave does not need a medium to transfer energy through.
Physics
2 answers:
ankoles [38]2 years ago
7 0
<h3><u>Answer;</u></h3>

<em>A mechanical wave transfers energy through matter</em>

<h3><u>Explanation;</u></h3>
  • A<em><u> wave is a transmission of a disturbance </u></em>from one point to another. Wave<u><em> involves transmission of energy from one point to another through a materials medium.</em></u>
  • Waves may require or may nor require a material medium for transmission. Those wave that do not require material medium for transmission are electromagnetic waves while <em><u>those that require material medium are called mechanical waves.</u></em>
  • <u><em>Mechanical waves</em></u> such as sound wave transfers energy from one point which is the wave source to another point through a material medium.
Westkost [7]2 years ago
3 0

The answer is "A mechanical wave transfers energy through matter."

I got it right on my quiz :)

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Jack travelled 360 km at an average speed of 80 km/h. Elaine
diamong [38]

Answer:

Average speed of Elain = 60 km/h

Explanation:

Total Distance covered by Jack = 360km

Average Speed of Jack = 80 km/h

Time taken by Jack to complete his journey = Distance / Average speed = 360 km / 80 km/h

Time taken by Jack to complete his journey = 4.5 hours

As it is given the both Jack and Elain travelled the same amount of distance:

Total distance travelled by Elain = 360 km

It is given that Elain took 1.5 hourse more than Jack to cover the distance, so Time taken by Elain to cover the distance is = 4.5 hours + 1.5 hours = 6 hours

Average speed of Elain = Distance/ time = 360 km / 6 hours

Average speed of Elain = 60 km/h

3 0
3 years ago
If 50 km thick crust having an average density of 3.0 g/cm3 has a surface elevation of 2.5 km above sea level, what would you pr
RUDIKE [14]

Answer:

To calculate the predicted surface elevation of a 50km thick crust above a surface of 2.5km we are given a density of 3 gram per centimeter cube.

The displacement of the material will be calculated by subtracting the surface elevation of 2.5 km from the 50 km thick crust. Therefore 50-25= 47.5 km.

Thus let the density of the material be Pm

50*3= 47.5*Pm

Therefore: Pm= (50*3)/47.5= 3.16gram per centimeter cube

Thus with an average density of 2.8gram per centimeter cube

50*2.8= (50-x)*3.16

(50-x)= (50*2.8)/3.16

50-x=44.3

x=50-44.3= 5.7

Explanation:

To calculate the predicted surface elevation of a 50km thick crust above a surface of 2.5km we are given a density of 3 gram per centimeter cube.

The displacement of the material will be calculated by subtracting the surface elevation of 2.5 km from the 50 km thick crust. Therefore 50-25= 47.5 km.

Thus let the density of the material be Pm

50*3= 47.5*Pm

Therefore: Pm= (50*3)/47.5= 3.16gram per centimeter cube

Thus with an average density of 2.8gram per centimeter cube

50*2.8= (50-x)*3.16

(50-x)= (50*2.8)/3.16

50-x=44.3

x=50-44.3= 5.7

5 0
3 years ago
State the difference between sensible heat and latent heat
Anna11 [10]

<u>Latent hea</u>t is related to changes in phase between liquids ,gases and solids.

<u>Sensible heat</u> is related to changes in temperature of a gas or object with no change in phase.

6 0
3 years ago
Three students have been studying relative motion and decide to do an experiment to demonstrate their knowledge. The experiment
miskamm [114]

Answer with Explanation:

We are given that

Constant speed of Jane=12.6 m/s

a.When Fred can throw the ball 30  m/s

We have to find the angle relative to the horizontal when he throw the ball in order for Sue to see the ball travel vertically upward.

Let \theta be the angle .

Therefore,

30 cos\theta=12.6

cos\theta=\frac{12.6}{30}=0.42

\theta=cos^{-1}(0.42)=65.165^{\circ}

b.We have to find the height to which ball reach.

v^2-v^2_0=2aS

S=\frac{v^2-v^2_0}{2a}=\frac{0-(30 sin65.165)^2}{2(-9.81)}

S=37.78 m

7 0
3 years ago
1. Si comprimes un globo hasta reducir su volumen a un tercio de su valor original, ¿cuánto aumenta la presión en su interior?
harina [27]

Answer:

See step by step sexplanation

Explanation:

1.-Sabemos que la relación:

P₁ * V₁  = P₂ * V₂

Para una temperatura constante debe mantenerse entonces si el globo se comprime hasta llevarlo a 1/3 de su valor inicial, entonces necesariamente para cumplir con la relación mencionada, la presión aumenta tres veces su valor original

2.-La definición de presión es fuerza por unidad de superficie, entonces la fuerza es determinada por la altura de la columna de liquido en el recipiente y no por la cantidad total de liquido, de acuerdo a esto habrá más presión en la base del florero, ya que la columna de agua tiene más altura.

3.-No se puede estar de acuerdo con el criterio del plomero. En su solución no plantea el aumento de la altura del tanque,  para el logro del aumento de la presión que es realmente lo que hay que hacer

4 0
3 years ago
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