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sweet-ann [11.9K]
2 years ago
11

Compare the mass on Neptune (68.11) to the weight on Neptune (905.863). What is the difference? Why is there a difference?

Physics
1 answer:
Alchen [17]2 years ago
7 0
Bbbjv. Jfuzuoud iuzTt45789
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Which of the following describes the renewability of utility-scale wind energy?
schepotkina [342]

Unlimited, clean energy plant describes the renewability of utility-scale wind energy.

<h3>What is utility-scale wind energy?</h3>

Utility-scale wind turbines are installed in large, multi-turbine wind farms connected to the nation's transmission system. These turbines produce clean and unlimited energy.

So we can conclude that Unlimited, clean energy plant describes the renewability of utility-scale wind energy.

Learn more about energy here: brainly.com/question/13881533

6 0
2 years ago
Calcula la resistencia de un conductor de cobre de 2 m de longitud y 0,1 m2 de sección. Resistividad del Cu = 1,7 · 10–8 Ω · m
Fudgin [204]

Answer:

an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).

5 0
2 years ago
Please Help me to find the answer...​
KonstantinChe [14]

Answer:

1. S-S Repulsion           N-S Attraction

2. S-N Attraction          N-N Repulsion

Explanation:

1. S-S Repulsion           N-S Attraction

2. S-N Attraction          N-N Repulsion

3 0
2 years ago
Un avión tarda en llegar a su destino 12 horas. Si recorrió una distancia de 10.700 kilómetros. Calcular su velocidad y expesarl
elixir [45]

Given that,

Distance, d = 10700 km

Time taken by the airplane to complete the destination, t = 12 hours

We need to find the speed of the airplane. It is equal to the total distance covered divided by total time taken. So,

v=\dfrac{d}{t}\\\\v=\dfrac{10700\ km}{12\ h}\\\\v=891.66\ km/h

We know that,

1 km = 1000 m

1 h = 3600 s

So,

v=891.66\ km/h =\dfrac{891.66\times 1000\ m}{3600\ s}\\\\v=247.68\ m/s

So, the speed of the airplane is 891.66 km/h or 247.68 m/s.

5 0
3 years ago
The driver of a 1750 kg car traveling on a horizontal road at 110 km/h suddenly applies the brakes. Due to a slippery pavement,
Alexeev081 [22]

Answer: a=-2.4525 m/s^2

d=s=190.3 m

Explanation:The only force that is stopping the car and causing deceleration is the frictional force Fr

Fr = 25% of weight

W=mg

W=1750*9.81

W=17167.5

Hence

Fr=\frac{25}{100} * -17167.5\\\\Fr=-4291.875 N

Frictional force is negative as it acts in opposite direction

According to newton second law of motion

F=ma

hence

a=Fr/m

a=-4291.875/1750\\a=-2.4525

given

u= 110 km/h

u=110*1000/3600

u=30.55 m/s

to get t we know that final velocity v=0

v^2=u^2+2as\\0=30.55^2-2*2.4525*s\\s=190.34m

3 0
2 years ago
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