Compare the mass on Neptune (68.11) to the weight on Neptune (905.863). What is the difference? Why is there a difference?

"Consider a 2-kg ball on the end of a 1-m long cord whose mass is negligible. The ball is swung in a horizontal circle and makes

qaws [65]

Explanation:

Below is an attachment containing the solution.

8 0

3 years ago

Explain the difference between speed and vilocity?

Zolol [24]

Answer:

The short answer is that velocity is the speed with a direction, while speed does not have a direction.

Explanation:

Speed is how fast an object is moving. It is calculated by the displacement of space per a unit of time. Velocity is the rate at which an object changes position in a certain direction. It is calculated by the displacement of space per a unit of time in a certain direction. Velocity deals with direction, while speed does not.

5 0

3 years ago

A 480 g peregrine falcon reaches a speed of 75 m/s in a vertical dive called a stoop. If we assume that the falcon speeds up und

Svet_ta [14]

The minimum height of the dive needed to achieve the given speed is v = 69 m/s is 242.9 m.

Given information:

The mass of peregrine falcon is, m = 480

The final speed reached by the peregrine falcon in a vertical dive is, v = 69 m/s

It is given that the falcon is diving vertically downward. It can be compared with the same situation as the free-falling object under the effect of gravity only. So, the initial velocity of the falcon will be u = 0 m/s as the motion starts with rest.

The value of the gravitational acceleration of gravity is, g = 9.80 m/s²

Now, using the third equation of motion, the minimum height required for the final speed will be,

v² - u² = 2gh

69² - 0² = 2 × 9.8 × h

h = 242.9m.

Therefore, the minimum height of the dive needed to achieve the given speed is 242.9 m.

Learn more about falcon speeds at

brainly.com/question/12449855

#SPJ4

6 0

2 years ago

A rock is dropped from a 110-m-high cliff. How long does it take to fall (a) the first 55.0 m and (b) the second 55.0 m?

Genrish500 [490]

Answer:

a) t = 3.35[s]; b) t = 1.386[s]

Explanation:

We can solve this problem by dividing it into two parts, for the first 55 [m] and then the second part with the remaining 55 [m].

We will take the initial velocity as zero, as the problem does not mention that the Rock was thrown at initial velocity.

And using kinematics equations:

$v_{f}^{2}= v_{o}^{2}+2*g*y\\where:\\v_{o}=0\\g=gravity = 9.81[m/s^2]\\y=55 [m]\\v_{f}^{2}=0+2*9.81*55\\v_{f}=\sqrt{2*9.81*55} \\v_{f}=32.85[m/s]$

Now we can calculate the time:

$v_{f}=v_{o}+g*t\\t=\frac{v_{f}-v_{o}}{g}\\ t=\frac{32.85-0}{9.81}\\ t=3.35[s]$

Now we can calculate the second time, but using as a initial velocity 32.85[m/s].

The final velocity will be:

$v_{f}^{2}= v_{o}^{2}+2*g*y\\v_{f}=\sqrt{v_{o}^{2}+2*g*y} \\v_{f}=\sqrt{32.85^{2}+2*9.81*55 } \\v_{f}=46.45[m/s]$

Now we can calculate the second time:

$t=\frac{46.45-32.85}{9.81} \\t= 1.386[s]$

Note: The reason the second time is shorter even though it is the same distance is that the acceleration of gravity increases the speed of the rock more and more as it falls.

7 0

3 years ago

A scientist measures the growth of a bamboo plant over time. The table

tatuchka [14]

Answer:does anyone know how to do this please

Explanation:

4 0

3 years ago