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statuscvo [17]
3 years ago
10

Enter the net ionic equation for the reaction of AgNO3(aq)

Chemistry
1 answer:
mixas84 [53]3 years ago
6 0

Answer:

Explanation:

This is a typical double replacement or double decomposition reaction. In this kind of reaction, it involves the combination of ionic compounds which exchange their partners to form new compounds. Typical of these reaction is the formation of precipitates which are insoluble compounds.

The reaction equation is shown below:

 AgNO₃(_{aq} ) + K₂SO₄(_{aq} ) → 2KNO₃(_{aq} ) + AgSO₄(_{s} )

From the rule of solubility:

  • All trioxonitrate(v) salts are soluble
  • Salts of silver sulfates are slightly soluble. This will form the precipitate in the solution.

We can write the ionic equation as:

      Ag⁺(_{aq} ) + NO₃⁻(_{aq} ) + 2K⁺(_{aq} ) + SO₄²⁻(_{aq} ) → AgSO₄(_{s} ) + 2K⁺ + NO₃⁻(_{aq} )

The spectator ions or non-reactive ions are those ions that appears on both sides of the equation. These ions are the potassium and trioxonitrate ions. We cancel them out to give the net ionic equation of the reaction:

 Ag⁺(_{aq} ) + SO₄²⁻(_{aq} ) → AgSO₄(_{s} )

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Answer:

See below

Explanation:

A chemist preforms the following: Neutralizing nitric acid (HNO3) with soda ash (Na2CO3). This reaction will then create sodium nitrate and carbonic acid, which will then decompose into water (H20)

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ch4aika [34]

Answer:

d. 1.2 × 1024

Explanation:

From the equation of reaction

2H2 + O2= 2H2O

i.e 2mole(4g) of hydrogen requires 1 mole(32g) of oxygen to produce 2mole (2×6.02×10^23 molecules) of H2O= 1.2×20^24 molcules of water.

NB: 1 mole of H2O contains 6.02×10^23 molecules of H2O

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What is the simplest formula of a compound if a sample of the compound contains 0.221 mol X, 0.442 mol Y, and 0.884 mol Z? chemP
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Answer:

XY₂Z₄

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Explanation:

A sample of the compound contains 0.221 mol X, 0.442 mol Y, and 0.884 mol Z. We can find the simplest formula (empirical formula) by <em>dividing all the numbers of moles by the smallest one</em>.

X: 0.221/0.221 = 1

Y: 0.442/0.221 = 2

Z: 0.884/0.221 = 4

The simplest formula is XY₂Z₄.

The molar ratio of X to Z is 1:4. The moles of Z in a sample that contained 0.588 moles of X is:

0.588 mol X × (4 mol Z/1 mol X) = 2.35 mol Z

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