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Dafna11 [192]
2 years ago
8

Which statement below represents the meaning of the phase "diffusion of innovation".

Mathematics
1 answer:
Viktor [21]2 years ago
3 0

Answer:

there is no statement for that phrase

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What percent of 4c in each expression? <br> 0.2c
Ymorist [56]

The percentage of 4c in the expression 0.2c is 2000%

<h3>How to determine the percentage of 4c?</h3>

The expression is given as:

0.2c

The percentage of 4c is then calculated as:

4c/0.2c

Evaluate the quotient

20

Express as percentage

2000%

Hence, the percentage of 4c in 0.2c is 2000%

Read more about percentages at:

brainly.com/question/843074

#SPJ1

7 0
1 year ago
Tell whether the relationship is a proportional relationship. if so, give the constant of proportionality
SVETLANKA909090 [29]
Proportional because it's a straight line if you follow the graph points and it goes by 5
5 0
3 years ago
What is the value of x
Marat540 [252]
X is 12, I did this question to someone else before
7 0
2 years ago
45 +2.50m = 3.75m<br> what is the answer
zhannawk [14.2K]

m = 36

<u>Work</u>

<em>45 + 2.50m = 3.75m</em>

<em>        -3.75m    -3.75m</em>

<em>45 - 1.25m = 0</em>

<em>- 45             - 45</em>

<u><em>-1.25</em></u><em>m = </em><u><em>-45</em></u>

<em>-1.25     -1.25</em>

<em>     </em>m = 36

3 0
3 years ago
A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find
Ratling [72]

Answer:

Area of the garden:

\begin{equation*} 398.93\text{ ft}^2 \end{equation*}

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}

Let's now go ahead and determine the area of the semicircle using the below formula;

A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2

Let's also determine the area of the rectangle;

A_r=l*w=23*14=322\text{ ft}^2

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}

Therefore, the area of the garden is 398.93 ft^2

8 0
1 year ago
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