Answer:
To prove that 3·4ⁿ + 51 is divisible by 3 and 9, we have;
3·4ⁿ is divisible by 3 and 51 is divisible by 3
Where we have;
= 3·4ⁿ + 51
= 3·4ⁿ⁺¹ + 51
-
= 3·4ⁿ⁺¹ + 51 - (3·4ⁿ + 51) = 3·4ⁿ⁺¹ - 3·4ⁿ
-
= 3( 4ⁿ⁺¹ - 4ⁿ) = 3×4ⁿ×(4 - 1) = 9×4ⁿ
∴
-
is divisible by 9
Given that we have for S₀ = 3×4⁰ + 51 = 63 = 9×7
∴ S₀ is divisible by 9
Since
-
is divisible by 9, we have;
-
=
-
is divisible by 9
Therefore
is divisible by 9 and
is divisible by 9 for all positive integers n
Step-by-step explanation:
Answer:
<em>29 minutes more</em>
Step-by-step explanation:
Let m represent minutes
changing the statement to algebra, since the second company charges a different rate at night and weekend we have the equation below;
$19.99 + $0.35m > $29.99
Subtract 19.99 from both sides to isolate m and we have;
$19.99 -$19.99 + $0.35 > $29.99 - $19.99
= $0,35m > $10.00
Divide both side by 0.35 to obtain the value of m;
> 
= m > 28.57
<em>m ⩾ 29 minutes</em>
<em>The second company's will be twenty nine minutes or more costlier than the first company</em>
From the relation, d is joint proportionaly with r and t.
Thus,d = krt.
Using the first set of given, we could calculate for k.135 = k(45)(3)k = 1
Using the computed value of k.d = krtr = d/ktr = (189)/(1)(3.5) = 54 mph.
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Answer:
y=+3
Step-by-step explanation: