Question

Write the equation for a parabola that has x-intercepts (−4.5, 0) and (−2.8, 0) and y-intercept (0, 37.8).

Answer 1

Answer:

$y=3(x+4.5)(x+2.8)$ or  $y=3x^2+21.9x+37.8$

Step-by-step explanation:

we know that

The equation of a vertical parabola in factored form is equal to

$y=a(x-x_1)(x-x_2)$

where

a is a coefficient

x_1 and x_2 are the roots or x-intercepts of the quadratic equation

In this problem we have

$x_1=-4.5\\x_2=-2.8$

substitute

$y=a(x+4.5)(x+2.8)$

Find the value of a

we have the y-intercept (0,37.8)

substitute the value of x and the value of y of the y-intercept in the equation and solve for a

$37.8=a(0+4.5)(0+2.8)$

$a=37.8/12.6\\a=3$

so

$y=3(x+4.5)(x+2.8)$

Convert to expanded form

$y=3(x^2+2.8x+4.5x+12.6)$

$y=3x^2+21.9x+37.8$

Answer 2

Answer:

Go to the link below :)

Step-by-step explanation:

brainly.com/question/14380301