Can someone explain how the weight of the block is 10.26N, with reference to an appropriate law of motion?
1 answer:
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Answer:
The total distance traveled by the car (S) = 15 mi
Explanation:
Total acceleration () = 10 mi /
Time (t) = 1 hour
Deceleration () = - 5 mi /
From law of speed we know that V = u + t -----------(1)
Where V = Final speed
u = initial speed and t = time period
Car starts from rest so initial speed is zero so u = 0
Then equation 1 becomes V = t = 10 × 1 = 10 mi / h ---------(2)
The distance traveled by the car = u t +
×
×
-------------(3)
Put all the values in equation we get = 0 +
× 10 ×
= 5 mi ---------------(4)
This is the distance traveled by the car in 1 hour.
In second case when car starts decelerates the equation of motion becomes
⇒ V = u - a t -----------(5)
final speed in this case = 0 and initial speed (u) = 10 mi / h
⇒ 0 = 10 - 5 t
⇒ 5 t = 10
⇒ t = 2 hours
Distance traveled by the car in to hours = u t +
×
×
⇒ = 10 × 2 -
× 5 ×
⇒ = 20 - 10
⇒ = 10 mi
This is the distance traveled by the car in the next two hours.
Thus the total distance traveled by the car = +
⇒ S = 5 + 10 = 15 mi
Given k=100, Area if plate A = 1.00 cm2
Thickness of rutile
Without any dielectric medium capacitance of a parallel plate capacitor is c = oAd
When a dielectric is placed between capacitors plates then capacitance c1 = KoAd
Here ,
Now
Correct Option: A
What purposes serve parallel plate capacitors?
The following are some uses for parallel plate capacitors:
- This kind of capacitor is utilized in rechargeable energy systems such as batteries.
- These capacitors are used in systems for dynamic digital memory.
- Such capacitors are used in pulsed laser and radar circuits.
To learn more about Parallel plate capacitors, visit:
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