1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Soloha48 [4]
4 years ago
5

Dos cargas q_1=-8μC y q_2=13μC se encuentran a una distancia r=0.12 m. ¿Cuál es la fuerza resultante sobre una tercera carga q_3

=-4μC, situada en el centro de la distancia que separa las cargas q_1 y q_2?
Physics
1 answer:
KiRa [710]4 years ago
8 0

Answer:

209.53 N

Explanation:

To find the force on the third charge you use the Coulomb formula:

F=k\frac{q_1q_2}{r^2}

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

The force on the third charge is the contribution of the force between the third charge and the other ones:

F=F_1+F_2

By taking into account that the third charge is at the middle of the distance between charge 1 and charge 2 you have r = 0.12m/2 = 0.06m

Furthermore, you take into account that the first charge repels the third charge and the second charge attracts the third charge.

By replacing you have:

F=k\frac{q_1q_3}{r^2}+k\frac{q_2q_3}{r^2}\\\\F=\frac{k}{r^2}q_3[q_1+q_2]\\\\F=\frac{(8.98*10^9Nm^2/C^2)(4*10^{-6}C)}{(0.06m)^2}[8*10^{-6}C+13*10^{-6}C]\\\\F=209.53\ N

Hence, the force between on the third charge is 209.53 N

You might be interested in
What is the net power needed to change the speed of a 1600-kg sport utility vehicle from 15.0 m/s to 40.0 m/s in 4.00 seconds
Sergio039 [100]

Answer:

The net power needed to change the speed of the vehicle is 275,000 W

Explanation:

Given;

mass of the sport vehicle, m = 1600 kg

initial velocity of the vehicle, u = 15 m/s

final velocity of the vehicle, v = 40 m/s

time of motion, t = 4 s

The force needed to change the speed of the sport vehicle;

F = \frac{m(v-u)}{t} \\\\F = \frac{1600(40-15)}{4} \\\\F = 10,000 \ N

The net power needed to change the speed of the vehicle is calculated as;

P_{net} = \frac{1}{2} F[u + v]\\\\P_{net} = \frac{1}{2} \times 10,000[15 + 40]\\\\P_{net} = 275,000 \ W

3 0
3 years ago
What spheres are part of the earths system​
Mama L [17]

Answer:

northern and southern sphere

Explanation:

4 0
3 years ago
Read 2 more answers
Name two objects that have a high density.
Sonbull [250]

Answer:

Iron and stone

Explanation:

4 0
4 years ago
4. The blades on a fan have a frequency of 15 Hz.
vichka [17]

Answer:

a) 4500 cycles b) 0.0667s c) 6.67s

Explanation:

a) 15 Hz= 15 cycles/ s

   5 mins= 300s

   15 cycles/s * 300s= 4500 cycles

b) Period= 1/ frequency

   Period= 1/ 15 cycles/s

   Period= 0.0667s

c) Period * number of revolutions= time

  0.0667 * 100= 6.67s

6 0
3 years ago
How much energy or stopping power is needed to bring a car to a stop from 100 mph?
Fed [463]
I think 100 mph pushing the car the opposite direction
3 0
3 years ago
Other questions:
  • Consider an electric dipole, composed of charges +q and -q separated by distance d, that is viewed from a large distance (large
    11·1 answer
  • Answer and I will give you brainiliest
    7·1 answer
  • 1. Find the current ix in the circuits in Fig. E2.6.
    11·1 answer
  • In the video, you saw that models must sometimes be changed. why does that happen?
    5·2 answers
  • A cannonball is fired across a flat field at an angle of 43 degrees with an initial speed 32 m/s and height of 12 m.
    6·1 answer
  • (Brainliest) How are radio waves used in cell phone wireless communication technology?
    12·1 answer
  • 1. The unit of power is called a derived unit, why?
    9·1 answer
  • A rock that has magnetic properties is
    7·1 answer
  • True/False: The core, mantle, and crust explanation for the Earth's layers is outdated and now we use the 5 layer explanation. *
    10·1 answer
  • Q1) An action exerted on an object which may change the object's
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!