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Soloha48 [4]
3 years ago
5

Dos cargas q_1=-8μC y q_2=13μC se encuentran a una distancia r=0.12 m. ¿Cuál es la fuerza resultante sobre una tercera carga q_3

=-4μC, situada en el centro de la distancia que separa las cargas q_1 y q_2?
Physics
1 answer:
KiRa [710]3 years ago
8 0

Answer:

209.53 N

Explanation:

To find the force on the third charge you use the Coulomb formula:

F=k\frac{q_1q_2}{r^2}

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

The force on the third charge is the contribution of the force between the third charge and the other ones:

F=F_1+F_2

By taking into account that the third charge is at the middle of the distance between charge 1 and charge 2 you have r = 0.12m/2 = 0.06m

Furthermore, you take into account that the first charge repels the third charge and the second charge attracts the third charge.

By replacing you have:

F=k\frac{q_1q_3}{r^2}+k\frac{q_2q_3}{r^2}\\\\F=\frac{k}{r^2}q_3[q_1+q_2]\\\\F=\frac{(8.98*10^9Nm^2/C^2)(4*10^{-6}C)}{(0.06m)^2}[8*10^{-6}C+13*10^{-6}C]\\\\F=209.53\ N

Hence, the force between on the third charge is 209.53 N

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A ball is dropped from rest at height of 20m. If it loses 25% of its kinetic energy when it strikes the ground. What is the heig
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Answer:

15 meters

Explanation:

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In the moment that the ball strickes the ground, all potencial energy transformed into kinetic energy, and 25% of this energy is lost, so the total energy at this moment will be:

E' = 0.75 * E = 0.75 * m * g * 20 = 15*m*g

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E' = m*g*h = 15*m*g -> h = 15 meters

6 0
3 years ago
A particular form of electromagnetic radiation has a frequency of 5.42x10^15 Hz. What is the wavelength is nanometers? meters?
zubka84 [21]
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icang [17]

Answer:

50 watts

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Applying,

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Given: F = 200 N, d = 0.5 m, t = 2 s

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7 0
2 years ago
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