A mass that weighs 10 lb stretches a spring 2.4 in. It rests in a liquid which imparts a dampening force of 4 pounds when the ve
locity is 2 ft/s. Assume the mass starts at equilibrium, with an initial downward velocity of 1 ft/s. (a) (6 points) Find the equation describing the position of the mass relative to equilibrium at any timet. (b) (2 points) Compute the natural frquency and the quasi frequency of the system (c) (2 points) Describe the behavior of the system as t 0.
1 answer:
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Answer:
g = 0.85 m
Explanation:
g =
were; g is the acceleration due to Earth's gravity, G is Newton's gravitation constant (6.674 x N
), M is the mass of the earth (5.972 x
kg), and h is the distance of meteoroid to the earth.
h = 3.40 x R
= 3.40 x 6371 km
h = 21661.4 km
= 21661400 m
Thus,
g =
=
= 0.84944
g = 0.85 m
The acceleration due to the Earth's gravitation is 0.85 m.