Complete Question
An L-C circuit has an inductance of 0.350 H and a capacitance of 0.290 nF . During the current oscillations, the maximum current in the inductor is 2.00 A .
What is the maximum energy 
stored in the capacitor at any time during the current oscillations?
Express your answer in joules.
Answer:
The value is 
Explanation:
From the question we are told that
The inductance is 
The capacitance is 
The current is 
Generally the maximum energy is mathematically represented as
=> 
=>
Answer:
The correct answer is "12 m/s²".
Explanation:
Given:
As we know,
⇒ 
Or,
⇒ 
By substituting the values, we get
⇒ 
⇒ 
⇒ 
Answer:
the average speed of the car during this time interval is 40 m/s i thinkk..
Answer:
3.06 m
Explanation:
The work done by the man against the gravity is given by
Where F is the force i.e. weight of the man and h is the displacement and 
is the angle between displacement and force
Since F=mg and is zero
W = mgh
Also, Work=power* time
Therefore, Power*time=mgh
Substituting power for 120 W, time for 20 seconds, g as 9.81 m/s2 and m as 80 Kg
120*20=80*9.81*h and making he the subject of the formula
Therefore, the height is approximately 3.06 m
Answer:
0.446 mm
0.066 V/m
Explanation:
Given
We are given the length of the copper cable L = 3.30 km and the potential difference is V = 220 V
Solution
(a) We want to find the diameter d of the cable when the dissipated power is P = 50W. The power consumed by the cable depends on its resistance R and it is given by equation in the form
P= V^2/R (1)
Where V is the voltage in the cable. Now let us solve equation (1) for R and plug our values for V and P into equation (1) to get R
R = V^2/P = (220)^2/(50) = 968Ω
Now we can determine the diameter of the copper wire. The resistance R of the wires depends on the area of the wire, resistivity and the length of the cable. Where equation gives us the relationship between these variables in the form
R = pL/π*r^2 (solve for r)
r = √pL/πR (2)
Now we can plug our values for Rep and L into equation (2) to get the radius of the cable where p for copper equals 1.72 x 10-8 Ω m
r =√pL/πR
= √1.72 x 10-8 *3300m/968
= 0.234 mm
Therefore, the diameter is d= 2r = 2(0.234 mm) = 0.446 mm
(b) To determine the electric field we can use the values for the potential difference across the cable and the length of the cable, where the electric field is inversely proportional to the length of the cable as next
E =V/L
=220/3300m
= 0.066 V/m
