A mass that weighs 10 lb stretches a spring 2.4 in. It rests in a liquid which imparts a dampening force of 4 pounds when the ve
locity is 2 ft/s. Assume the mass starts at equilibrium, with an initial downward velocity of 1 ft/s. (a) (6 points) Find the equation describing the position of the mass relative to equilibrium at any timet. (b) (2 points) Compute the natural frquency and the quasi frequency of the system (c) (2 points) Describe the behavior of the system as t 0.
1 answer:
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Answer:
Explanation:
It is given that, a proton moves at constant velocity, through a region in which there is an electric field and a magnetic field such that,
The electric field is, E = 800 V/m
Magnetic field, B = 0.25 T
We know that the net force in the region of magnetic and electric field is given by Lorentz forces. But here, the proton moves with constant velocity. So, the net force acting on it is 0.
i.e.
Hence, this is the required solution.
Answer:
400
Explanation:
Formula used in solution:
The given information:
Solution
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