A mass that weighs 10 lb stretches a spring 2.4 in. It rests in a liquid which imparts a dampening force of 4 pounds when the ve
locity is 2 ft/s. Assume the mass starts at equilibrium, with an initial downward velocity of 1 ft/s. (a) (6 points) Find the equation describing the position of the mass relative to equilibrium at any timet. (b) (2 points) Compute the natural frquency and the quasi frequency of the system (c) (2 points) Describe the behavior of the system as t 0.
1 answer:
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Answer:
22.02 m
Explanation:
given,
Force, F = 107 N
angle made with horizontal = 13.5◦
Power develop by the lawn roller = 69.4 W
time = 33 s
distance = ?
Force along horizontal= F cos θ
= 107 cos 13.5°= 104 N
Power =
69.4 =
W = 2290.2 J
Work done= Force x displacement
displacement=
= 22.02 m