4 years ago

Find the resultant of an easterly force of 100 N and a southeast force of 80 N acting at 65 degrees to the 100 N force

Physics

1 answer:

saveliy_v [14]4 years ago

7 0

Answer:

Resultant is 152 N at 28.5 degrees south to the 100 N force

Explanation:

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A boat race runs along a triangular course marked by buoys A, B, and C. The race starts with the boats headed west for 3700 mete

ale4655 [162]

Answer:

The last two bearings are

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Explanation:

Applying the Law of cosine (refer to the figure attached):

we have

x² = y² + z² - 2yz × cosX

here,

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Thus we have,

$cos X=\frac{x^2-y^2-z^2}{-2yz}$

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substituting the values in the equation we get,

$cos X=\frac{2900^2 + 3700^2-1700^2}{2\times 2900\times 3700}$

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similarly,

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$cos Y=0.649$

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Consequently, the angel Z = 180° - 49.50 - 26.47 = 104.02°

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