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oksian1 [2.3K]
4 years ago
13

How are LEDs more efficient than incandescent lights?

Physics
1 answer:
NeTakaya4 years ago
3 0
LED bulbs require much less wattage than the Incandescent light bulbs.

That’s why LED bulbs are much more long lasting and energy-efficient than the other types of bulb.
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Find out how the position of the Sun would be different at 12:00 midday in December than in June. What path would the sun take f
Ratling [72]

Answer:

Explanation: The Sun is directly overhead at solar noon at the Equator on the equinoxes, at the Tropic of Cancer (latitude 23°26′11.2″ N) on the June solstice and at the Tropic of Capricorn (23°26′11.2″ S) on the December solstice.

6 0
3 years ago
Describe how work done is related to a change in volume of a fluid. 100 points
Nookie1986 [14]

Answer: work is the pressure acting through the change in volume

Explanation:

In the same way that work is defined as force operating over a distance,  work is the pressure acting through the change in volume.   Pressure is comparable to force in pressure–volume work, while volume is analogous to distance in the classic definition of work.

4 0
2 years ago
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A fan uses 7A when connected to a 110V line. If electric power costs 10 cents per kilowatt-hour in this location, what is the co
Anna007 [38]
Power = current x voltage

So the power is 7 x 110 = 770 W = 0.77kW

0.77 x 13 = 10.01 kWh

10.01 x 10 cents = 100.1 cents (is this 1 dollar? Idk I use a different currency)
6 0
4 years ago
An electric field of intensity 3.25 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.
jekas [21]

Answer:

\varphi_1= 796.25 N m^2/C

\varphi_2= 0 N m^2/C

\varphi_3=686.1  N m^2/C

Explanation:

From the question we are told that

Electric field of intensity E= 3.25 kN/C

Rectangle parameter Width W=0.350 m  Length L=0.700 m

Angle to the normal \angle=30.5 \textdegree

Generally the equation for Electric flux at parallel to the yz plane \varphi_1 is mathematically given by

\varphi_1=EA cos theta

\varphi_1=3.25* 10^3 N/C * ( 0.350)(0.700) cos 0

\varphi_1= 796.25 N m^2/C

Generally the equation for Electric flux at parallel to xy  plane \varphi_2 is mathematically given by

\varphi_2=EA cos theta

\varphi_2=3.25* 10^3 N/C * ( 0.350)(0.700) cos 90

\varphi_2= 0 N m^2/C

Generally the equation for Electric flux at angle 30 to x plane \varphi_3 is mathematically given by

\varphi_3=EA cos theta

\varphi_3=3.25* 10^3 N/C * ( 0.350)(0.700) cos 30.5

\varphi_3=686.072219  N m^2/C

\varphi_3=686.1  N m^2/C

7 0
3 years ago
Which shows the correct lens equation?
zhuklara [117]

Answer:

The inverse of f equals the inverse of d Subscript o Baseline plus the inverse of d Subscript I Baseline.

Explanation:

Explanation:

5 0
3 years ago
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