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enyata [817]
4 years ago
6

A fan uses 7A when connected to a 110V line. If electric power costs 10 cents per kilowatt-hour in this location, what is the co

st of running the fan for 13 hours?
Physics
1 answer:
Anna007 [38]4 years ago
6 0
Power = current x voltage

So the power is 7 x 110 = 770 W = 0.77kW

0.77 x 13 = 10.01 kWh

10.01 x 10 cents = 100.1 cents (is this 1 dollar? Idk I use a different currency)
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Hi :) I don’t really understand why it’s A
Troyanec [42]

Answer:

A

Explanation:

1. When the block moves across a table top, F(pulling) = - F(frictional).

Sum of this forces = 0, so the block moves with uniform speed.

2. When the block is pulled on top of the table covered with beads

F(pulling) > - F(frictional).

So, the sum of forces (∑F) is a number that is more than 0 and directed to the direction of movement.

So,  a = ∑F / m is positive and constant. Speed is increasing because

v(t) = v(0)+at

a is constant and  directed forward.

That means a is acceleration, and constant.

6 0
4 years ago
A person starts at a position of 16 meters and finishes at a position of
DochEvi [55]

Answer:

38 is a good girl and a great place to work for u and I miss you y and I miss you much love your love and love to

7 0
3 years ago
Two nuclear reactors provide 3200 MW of power.If the transmission system loses 5.1% of the energy produced,how much power from t
Annette [7]

The power that the customers receive is 163.2 MW

Explanation:

The efficiency of a system is given by

\eta = \frac{P_{out}}{P_{in}}

where

P_{out} is the power in output

P_{in} is the power in input

For the nuclear reactors in this problem, we have:

P_{in} = 3200 MW (power generated by the reactors)

\eta=0.051 (efficiency is 5.1%)

Therefore, the power that reaches the customers is:

P_{out} = \eta P_{in} = (0.051)(3200)=163.2 MW

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

6 0
3 years ago
5. Which of the following is velocity? *
ivann1987 [24]
A. 20m/s because the unit for velocity is m/s
3 0
3 years ago
A car is traveling at 108 km/h, stuck behind a slower car. Finally the road is clear and the car pulls over to make a pass. The
mezya [45]

Answer:

The average acceleration of the car is 2.143 meters per square second.

Explanation:

Let assume that car accelerates uniformly, in that case, we can obtain the value of acceleration by using the following equation of motion:

v = v_{o}+a\cdot t

Where:

v_{o} - Initial velocity, measured in meters per second.

v - Final velocity, measured in meters per second.

a - Acceleration, measured in meters per square second.

t - Time, measured in seconds.

Now, we clear acceleration within expression:

a = \frac{v-v_{o}}{t}

Initial and final velocities are now converted from kilometers per hour into meters per second:

v_{o} = \left(108\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

v_{o} = 30\,\frac{m}{s}

v = \left(135\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

v = 37.5\,\frac{m}{s}

If we know that t = 3.5\,s, then, the average acceleration of the car is:

a = \frac{37.5\,\frac{m}{s}-30\,\frac{m}{s} }{3.5\,s}

a = 2.143\,\frac{m}{s^{2}}

The average acceleration of the car is 2.143 meters per square second.

8 0
3 years ago
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