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Vinil7 [7]
4 years ago
5

Which is a characteristic of mixtures?

Chemistry
2 answers:
Vesna [10]4 years ago
7 0
This correct Sancerre is that they can be separated by a physical process
siniylev [52]4 years ago
6 0

Answer:

The correct answer is "They can be separated by physical processes"

Explanation:

The definition of Mixtures is <em>the blending of two or more dissimilar substances</em>.

Mixtures can be divided into those that are homogeneous or heterogeneous meaning that they can be distributed evenly or can't be distributed evenly.

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I NEED UR HELPPPP I HAVE TO SUBMIT IT IN 10 MINS!!!! PLEASE I HAVE NO IDEA
Vilka [71]

Explanation:

6/t1=4/293= 1750/4 =439.5-273=166.5

4 0
3 years ago
compound consists of carbon, hydrogen and fluorine. In one experiment, combustion of 2.50 g of the compound produced 3.926 g of
arlik [135]

<u>Answer:</u> The empirical and molecular formula of the compound is CH_2F and C_{14}H_{28}F_{14}  respectively

<u>Explanation:</u>

We are given:

Mass of CO_2=3.926g

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.926 g of carbon dioxide, \frac{12}{44}\times 3.926=1.071g of carbon will be contained.

To calculate the percentage composition of element in sample, we use the equation:

\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100      ......(1)

  • <u>For Carbon:</u>

Mass of carbon = 1.071 g

Mass of sample = 2.50 g

Putting values in equation 1, we get:

\%\text{ composition of carbon}=\frac{1.071g}{2.50g}\times 100=42.84\%

  • <u>For Fluorine:</u>

Mass of fluorine = 2.54 g

Mass of sample = 5.00 g

Putting values in equation 1, we get:

\%\text{ composition of fluorine}=\frac{2.54g}{5.00g}\times 100=50.8\%

Percent composition of hydrogen = [100 - 42.84 - 50.8] % = 6.36 %

We are given:

Percentage of C = 42.84 %

Percentage of F = 50.8 %

Percentage of H = 6.36 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 42.84 g

Mass of F = 50.8 g

Mass of H = 6.36 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.84g}{12g/mole}=3.57moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{6.36g}{1g/mole}=6.36moles

Moles of Fluorine = \frac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}=\frac{50.8g}{19g/mole}=2.67moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.67 moles.

For Carbon = \frac{0.072}{2.67}=1.34\approx 1

For Hydrogen = \frac{6.36}{2.67}=2.38\approx 2

For Fluorine = \frac{2.67}{2.67}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : F = 1 : 2 : 1

The empirical formula for the given compound is CH_2F

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 448.4 g/mol

Mass of empirical formula = 12+(2\times 1)+19]=33g/mol

Putting values in above equation, we get:

n=\frac{448.4g/mol}{33g/mol}=13.6\approx 14

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(14\times 1)}H_{(14\times 2)}F_{(14\times 1)}=C_{14}H_{28}F_{14}

Hence, the empirical and molecular formula of the compound is CH_2F and C_{14}H_{28}F_{14}  respectively

3 0
3 years ago
Each nucleus of a cell contains:
Jobisdone [24]

Hi there!

<u>Answer</u>:

Genes and chromosomes

Explanation:

All cells contain Genetic information (or Dna) which is organised into structures called chromosomes.

Chlorophyll are basically green pigments in Chloroplasts and both are <u>only</u><u> </u><u> </u><u> </u><u> </u>found in plant cells and not all cells

5 0
3 years ago
Copper atoms are used to produce pennies. The copper atoms in pennies share many electrons. Pennies contain
kaheart [24]

Answer:

Metallic bonds

Explanation:

Metallic bonds joins atoms of metals and atoms of alloys together. The copper used in making pennies is a metallic substance so it contains metallic bonds.

  • The formation of this bond type is predicated on the large atomic radius, low ionization energy and large number of electrons in the valence shell.
  • The bond is an attraction between the positive nuclei of all closely packed atoms in the lattice and the electron cloud.
  • The electron cloud is jointly formed by all the atoms by losing their outermost shell electrons.

This way the bond in pennies are metallic in nature.

5 0
3 years ago
A reaction occurs in which hydrogen-1 and hydrogen-2 form helium-3. Is this a chemical reaction or a nuclear reaction, and how d
olga nikolaevna [1]
Cause -3 is -3sjsnsnsnsnsnnsnsnsnnsnsnsnsn
7 0
3 years ago
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