1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MaRussiya [10]
2 years ago
13

How does the amount of baking soda used affect the size of the cookie baked?

Chemistry
1 answer:
olganol [36]2 years ago
6 0
Baking soda is a reactant which means it makes the cookie bigger. So when using a lot of baking soda the cookie will be big
You might be interested in
Predict the decay process and write the nuclear equation of Cf- 255
matrenka [14]

Answer:

curium

−

243

,

252

/

99

Es,  

251

/

98

Cf,  

214

/

82

Pb

Explanation: Im not very good with this but here ya go!

8 0
2 years ago
Increasing the temperature of a solution will slow down the dissolving/dissolution of the solute.
expeople1 [14]

Answer:

False

Explanation:

It will actually speed it up

7 0
3 years ago
The stability of atomic nuclei is most affected by the
KengaRu [80]
D. Ratio of Neutrons to Protons
8 0
2 years ago
In a unimolecular reaction with twice as much starting material as product at equilibrium, what is the value of Keq? Is ΔG o pos
lubasha [3.4K]

Answer : The value of K_{eq} is, 0.5 and \Delta G= positive.

Explanation :

The unimolecular reaction is:

A\rightarrow B

In unimolecular reaction, the starting material is 2 times to the product.

A=2B      .........(1)

As we know that:

K_{eq}=\frac{B}{A}     ...........(2)

Now substitute equation 1 in 2, we get:

K_{eq}=\frac{\frac{A}{2}}{A}

K_{eq}=0.5

Now we have to calculate the value of \Delta G^o at 298 K.

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy = ?

R = gas constant = 8.314 J/mol.K

T = temperature = 298 K

K_{eq} = equilibrium constant = 0.5

Now put all the given values on the above formula, we get:

\Delta G^o=-(8.314J/mol.K)\times (298K)\ln (0.5)

\Delta G^o=1717.32J/mol

Thus, the value of \Delta G^o at 298 K is, 1717.32 J/mol

As we know that:

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

Thus, the \Delta G= +ve. So, the reaction is non spontaneous.

8 0
3 years ago
Please help me I will give you the brain thing and extra points. 2
oee [108]
I think it’s A but, don’t come at me if I’m wrong. Btw I read over it multiple times so this isn’t a random guess. Good luck tell me if you got it right
7 0
2 years ago
Read 2 more answers
Other questions:
  • At what temp will a gas be at if you allow it to expand from an original 456 mL to 65°C to 3.4 L
    11·2 answers
  • Which is an acceptable Lewis structure for a diatomic nitrogen molecule?
    15·2 answers
  • While David was riding his bike around the circular cul-de-sac by his house he wondered if the constant circle motion was having
    11·1 answer
  • What is meant by the statement "saturated hydrocarbons are relatively inert"?
    12·1 answer
  • Oxygen is composed of only one kind of atom and can’t be separated into simpler substances. What type of matter is it?
    14·2 answers
  • Which objects could you stand near to feel the heat​
    12·1 answer
  • A reversible reaction is said to be in equilibrium when
    5·1 answer
  • To completely neutralise 200cm3 of 0.5mol/dm3 sodium hydroxide (NaOH), a student adds 100cm3 of 0.5mol/dm3 sulfuric acid (H2SO4)
    7·1 answer
  • WW
    9·1 answer
  • Cual es la convención de 746 Hm
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!