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Zarrin [17]
3 years ago
6

Calculate the enthalpy of combustion of 1 mol decane, C10H22, (l), to form CO2 and H2O. ∆Hf0 for decane is —300.9 kJ/mol using t

he balanced chemical equation and Appendix Table B–14.
Chemistry
1 answer:
worty [1.4K]3 years ago
5 0

Answer:

heyy do you got the answer? i got that cuestion but i need the answer!!! did you finally get it?

Explanation:

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At the end of the reaction you washed the chemicals into a beaker using water. Why was it OK to use water to do this if Grignard
lesya692 [45]

Answer: water could be used to wash it since the reaction has ended.

Explanation:

There will be no reaction of water with the Grignard reagent since the reaction has ended, as it is well known that water is a universal solvent for washing of glasswares after experiments but if it is during the reaction it will be more advisable to rinse with alcohol to enhance more accuracy during the experiment

7 0
3 years ago
Read the reaction and the statement. H2(g) + I2(g) ⇌ 2HI(g) The concentration of H2, I2 and HI are measured as 0.04 M, 0.08 M an
hjlf

Answer:

45467777777777yt3457942

4 0
3 years ago
The smallest ionic radius among the following. <br> Li<br> Mg<br> Na+<br> be+
dimaraw [331]
The correct answer is Be+

That is because it lost a single electron but still has the same number of protons, and thus the effective charge attracting each electron is greater, which in turn makes the radius even smaller
5 0
3 years ago
, Hydrocarbons are compounds that contain(1) carbon, only(2) carbon and hydrogen, only(3) carbon, hydrogen, and oxygen, only(4)
Firdavs [7]
Hydrocarbons are compounds formed by only hydrogen atoms and carbon.

Answer (2)

hope this helps!
4 0
3 years ago
A pump contains 0.5 L of air at 203kPa. You draw back on the piston of the pump until the pressure reads 25.4kPa. What is the vo
densk [106]
<h3><u> Answer</u>;</h3>

= 4.0 L

<h3><u>Explanation;</u></h3>

Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to pressure at a constant temperature.

Therefore; <em>Volume α 1/pressure</em>

<em>Mathematically; V α 1/P</em>

<em>V = kP, where k is a constant;</em>

<em>P1V1 = P2V2</em>

<em>V1 = 0.5 l, P1 =203 kPa, P2 = 25.4 kPa</em>

<em>V2 = (0.5 × 203 )/25.4 </em>

<em>     = 3.996 </em>

<em>    ≈ </em><em><u>4.0 L</u></em>

6 0
3 years ago
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