Answer: Concentration of 
in the equilibrium mixture is 0.31 M
Explanation:
Equilibrium concentration of 
= 0.729 M
The given balanced equilibrium reaction is,
Initial conc. x 0 0
At eqm. conc. (x-2y) M (y) M (3y) M
The expression for equilibrium constant for this reaction will be:
3y = 0.729 M
y = 0.243 M
![K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5By%5D%5Ctimes%20%5B3y%5D%5E3%7D%7B%5Bx-2y%5D%5E2%7D)
Now put all the given values in this expression, we get :
concentration of in the equilibrium mixture = 
Thus concentration of in the equilibrium mixture is 0.31 M
Explanation:
13 are the number of atoms
N₂H₄ + 2H₂O₂ → N₂ + 4H₂O
mol = mass ÷ molar mass
If mass of hydrazine (N₂H₄) = 5.29 g
then mol of hydrazine = 5.29 g ÷ ((14 ×2) + (1 × 4))
= 0.165 mol
mole ratio of hydrazine to Nitogen is 1 : 1
∴ if moles of hydrazine = 0.165 mol
then moles of nitrogen = 0.165 mol
Mass = mol × molar mass
Since mol of nitrogen (N₂) = 0.165
then mass of hydrazine = 0.165 × (14 × 2)
= 4.62 g
Answer:
1.2,dibromoethane is the sha'awa .
<h2>Let us solve for it </h2>
Explanation:
Energy
It is ability to do work .
There are so many forms of energy .
out of which mechanical energy is also one of the form .
Mechanical energy
It is the energy possessed by the body by virtue of its motion and state .
It is of two types :
- Kinetic energy
- Potential energy
Kinetic energy
It is the energy possessed by the body by virtue of its motion .
Its expression is :
K.E=1/2mv²
Here in above question it is given that :
mass = 2Kg
V=10m/sec
K.E will be = 1/2 x 2 x 10 x 10
K.E=100 J
