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jok3333 [9.3K]
2 years ago
15

The pH of a 0.05 M solution of acetic acid is 3. What is the value of the equilibrium constant for the dissociation of acetic ac

id?
Chemistry
1 answer:
Leokris [45]2 years ago
5 0

Answer:

k = 2,04x10⁻⁵

Explanation:

The equilibrium of acetic acid (CH₃COOH) in water is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺.

And the equilibrium constant is defined as:

k = [CH₃COO⁻] [H⁺] / [CH₃COOH] <em>(1)</em>

The equiibrium concentration of each specie if the solution of acetic acid is 0,05M is:

[CH₃COOH] = 0,05M - x

[CH₃COO⁻] = x

[H⁺] = x

<em>-Where x is the degree of reaction progress-</em>

As the pH is 3, [H⁺] = 1x10⁻³M. That means x =  1x10⁻³M

Replacing in (1):

k = (1x10⁻³)² / 0,05 - 1x10⁻³

k = 1x10⁻⁶ / 0,049

<em>k = 2,04x10⁻⁵</em>

<em></em>

I hope it helps!

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The amount left after 20 years = 154.15 mg

<h3>Further explanation </h3>

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The decay formula for isotope :

\tt \large{\boxed{\bold{A(t)=217e^{-0.0171t}}}

Then for t=20 years, the amount left :

\tt A(t)=217e^{-0.0171\times 20}\\\\A(t)=154.15~mg

4 0
3 years ago
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Answer:

The volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml

Explanation:

Here we have the reaction of AgNO₃ and NaCl as follows;

AgNO₃(aq) + NaCl(aq)→ AgCl(s) + NaNO₃(aq)

Therefore, one mole of silver nitrate, AgNO₃, reacts with one mole of sodium chloride, NaCl, to produce one mole of silver choride, AgCl, and one mole of sodium nitrate, NaNO₃,

Therefore, since 5.84 grams of NaCl which is 58.44 g/mol, contains

Number \, of \, moles, n  = \frac{Mass}{Molar \ mass} =  \frac{5.84}{58.44} = 0.09993 \ moles \ of \ NaCl

0.09993 moles of NaCl will react with 0.09993 moles of AgNO₃

Also, as 1.0 M solution of AgNO₃ contains 1 mole per 1 liter or 1000 mL, therefore, the volume of AgNO₃ that will contain 0.09993 moles is given as follows;

0.09993 × 1 Liter/mole= 0.09993 L = 99.93 mL

Therefore, the volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml.

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3 years ago
If the melting point of a certain amount of a solid is 50 degrees, what is the melting point of half that amount of the solid? 5
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The answer is 25 degrees.
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g A microwave oven heats by radiating food with microwave radiation, which is absorbed by the food and converted to heat. If the
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Answer:

The total photons required = 5.19 × 10²⁸ photons

Explanation:

Given that:

the radiation wavelength λ= 12.5 cm = 0.125 m

Volume of the container = 0.250 L = 250 mL

The density of water = 1 g/mL

Density = mass /volume

Mass =  Volume ×  Density

Thus; the mass of the water =  250 mL ×  1 g/mL

the mass of the water = 250 g

the specific heat of water s = 4.18 J/g° C

the initial temperature T_1 = 20.0° C

the final temperature T_2 = 99° C

Change in temperature \Delta T = (99-20)° C = 79 ° C

The heat q absorbed during the process = ms \Delta T

The heat q absorbed during the process = 250 g × 4.18 J/g° C × 79° C

The heat q absorbed during the process = 82555 J

The energy of a photon can be represented by the equation :

= hc/λ

where;

h = planck's constant = 6.626 \times 10^{-34} \ J.s

c = velocity of light = 3.0 \times 10^8 \ m/s

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= 1.59024 \times 10^{-24} J

The total photons required = Total heat energy/ Energy of a photon

The total photons required = \dfrac{82555 J}{1.59024 \times 10^{-24}J}

The total photons required = 5.19 × 10²⁸ photons

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Answer:

384.2 K

Explanation:

First we convert 27 °C to K:

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With the absolute temperature we can use <em>Charles' law </em>to solve this problem. This law states that at constant pressure:

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We input the data:

300.16 K * 1600 m³ = T₂ * 1250 m³

And solve for T₂:

T₂ = 384.2 K

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2 years ago
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