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Elena L [17]
3 years ago
15

As the population in a small town grows, a new water treatment plant is built. The plant is built on a local river where it can

release treated water. The treated water is released downriver from the town. The town also gets its drinking water from further up the river.
How might the new treatment plant affect the ecosystem?

A. Treated water from the plant would affect communities downriver.
B. Treated water from the plant would affect communities upriver.
C. Treated water would affect this growing city’s drinking water.
Chemistry
1 answer:
xenn [34]3 years ago
7 0

Answer:

A. Treated water from the plant would affect communities downriver.

Explanation:

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Answer:

2 atoms of aluminium makes a molecule of aluminium

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While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by
grin007 [14]

Answer:

n_{C2H_5OH}^{eq}=14.234mol

Explanation:

Hello,

In this case, the reaction is:

C_2H_4+H_2O\rightleftharpoons CH_3CH_2OH

Thus, the law of mass action turns out:

Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}

Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change x result:

[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol

In such a way, the equilibrium constant is then:

Kc=\frac{\frac{x}{V} }{\frac{16mol}{V}* \frac{3mol}{V}} =\frac{\frac{13mol}{75.0L} }{\frac{16mol}{75.0L}* \frac{3mol}{75.0L}} =20.31

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

Kc=\frac{\frac{13+x_2}{V} }{\frac{16+15-x_2}{V}* \frac{3-x_2}{V}}  =20.31

Thus, the second change, x_2 finally result (solving by solver or quadratic equation):

x_2=1.234mol

Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:

n_{C2H_5OH}^{eq}=x+x_2=13mol+1.234mol\\n_{C2H_5OH}^{eq}=14.234mol

Best regards.

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Increase because of the higher the temp
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