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3 years ago

100 POINTS ANSWER FAST

Chemistry

2 answers:

alex41 [277]3 years ago

8 0

I believe the answer is a because 2 times 12 is 24. Hope this helped

love history [14]3 years ago

8 0

If im Correct it may be A, 24M

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What are the effects on the bodies of water? use terms algal bloom, dead zone and hypotoxic

Anna35 [415]

Water pollution is defined as the mixing of water with unwanted substances and that makes water unsafe.

Water pollution includes runoff of excess fertilizers,

herbicides, and insecticides from agricultural lands

and residential areas; oil, grease, and toxic chemicals

from urban runoff and energy production; and

sediment from improperly managed construction sites,

crop and forest lands, and eroding stream banks.

Polluted waters have high BOD which affects aquatic biodiversity.

Hpotoxic substances such as lead, arsenic, and fluoride cause many problems to aquatic animals and humans. Water contaminated with Arsenic results in diseases such as arsenicosis. Fluoride had been reported to cause depression in DNA and RNA synthesis in cultured cells, significant reductions in DNA and RNA levels, and conditions including aging, cancer, and arteriosclerosis are associated with DNA damage and its disrepair. Lead causes problems related to the central nervous system. Children and pregnant women are most at risk. Routine applications of fertilizers and pesticides for agriculture and uncontrolled runoff in water bodies. Adds nitrogen and phosphorus to water. It adds nitrogen and phosphorus to water causing eutrophication and algal blooms.

Therefore, all these activities make our water bodies a death zone for the marine ecosystem as well as humans.

To know more about water pollution, refer to the below link:

brainly.com/question/2976496

#SPJ4

8 0

1 year ago

A gas mixture with 4 mol of Ar, x moles of Ne, and y moles

maks197457 [2]

Answer:

a) $\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

b) $x=4$

c) $\Delta G_{max}=-2721.9 J/mol$

Explanation:

Gas mixture:

$n_{Ar}= 4 mol$

$n_{Ne}= x mol$

$n_{Xe}= y mol$

$n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}$

$n_{Ne} + n_{Xe}=2*n_{Ar}$

$x + y=8 mol$

$y=8 mol- x$

Mol fractions:

$x_{Ar}=\frac{4 mol}{12 mol}=1/3$

$x_{Ne}=\frac{x mol}{12 mol}=x/12$

$x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12$

Expression of $\Delta G_{mixing}$

$\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)$

$\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]$

$\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

Expression of $\Delta G_{max}$

$\frac{d \Delta G_{mixing}}{dx}=0$

$\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]$

$0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)$

$0=[ln (x/12)-ln ((8-x)/12)$

$ln (x/12)=ln ((8-x)/12)$

$x=(8-x)$

$x=4$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]$

$\Delta G_{max}=-2721.9 J/mol$

4 0

3 years ago

A tank in the shape of a rectangular prism measures 10 dm by 4 dm by 6 dm. the tank is completely filled with 8908.8 l of liquid

nevsk [136]

1) The question contains an unknown unit

The number 8908.8 has to be in units of mass: for example, kg or grams.

Here you indicated L.

I am going to work assuming that L is a mass unit. So you can see the way to solve the problem, but you have to verifiy the real unit of the statement and substitute with it.

With that in mind you can find the density of the liquid from:

density = mass / volume

2) Calculate the volume.

The volume of the liquid is the volume of the vessel, because it is filled.

The volume of the vessel is calculated from the formula of volume for a rectantular prism.

Volume of a rectangular prism = area of the base * height = side * side * height

=> Volume = 10 dm * 4 dm * 6 dm = 240 dm^3 = 240 liter

3) Calculate the density:

density = mass /volume = 8,908.8 L / 240 liter = 37.12 L / dm^3

Answer: 37.12 L / dm^3

6 0

3 years ago

If you are supposed to put in 2/4 a cup sugar for a recipe, can you just put in a half cup of sugar?

natta225 [31]

I would assume so.

Given $\frac{2}{4}$ , we can simplify the fraction to $\frac{1}{2}$

Both would obtain the same proportions, so I don't see why putting a half cup of sugar would make things any different.

Hope this is the answer you are looking for.

8 0

2 years ago

Read 2 more answers

What is the formula for calcium fluoride

MatroZZZ [7]

Answer:

$CaF_{2}$

Explanation:

Calcium = Ca

Fluorine = F

7 0

3 years ago

Read 2 more answers