Fluorine - 18.998 u
chromium - 51.996 u
tellurium - 127.6 u
dysprosium - 162.5 u
<span>Answer:
Enthalpy Change = (6 x -393.5) + (7 x -285.8) - (-204.6) + (19/2) 0.....???
like.. (6 x Enth CO2) + ( 7 x Enth H2O) - (Enth C6H14) + (19/2) Enth O2</span>
ZnO + 2HNO₃→ Zn(NO₃)₂ + H₂O
mol Zn(NO₃)₂ = mol ZnO = 0.2 (from the coefficient)
mass Zn(NO₃)₂ = 0.2 x 189 = 37.8 g (theorethical yield)
% yield = 15.3 : 37.8 x 100% = 40.48%
Answer:
0.15 L
Explanation:
You need to first find the volume of the container. You can do this by dividing the mass by the density. This will give you the mass in mL.
5.00 kg = 5,000 g
(5,000 g)/(1.00 g/mL) = 5,000 mL
5,000 mL = 5 L
Now, find the volume the seawater will take up.
(5,000 g)(1.03 g/mL) = 4854.4 mL
4854.4 mL = 4.85 L
Subtract the two volumes to find the volume that left unfilled.
5 L - 4.85 L = 0.15 L
