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The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.
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the specific heat capacity of the metal is 0.45 J/g⁰C.
The given parameters;
- <em>mass of water, </em>
<em> = 45 g</em>
- <em>final temperature of the water, </em>
<em> = 22 ⁰C</em>
- <em>mass of the metal, m = 8.5 g</em>
- <em>initial temperature of the metal, t = 82 ⁰C.</em>
- <em>specific heat capacity of the metal, c = 0.45 J/g⁰C.</em>
The initial temperature of the water will be calculated by applying the principle of conservation of energy;
<em>heat gained by water = heat lost by metal</em>
where;
<em>is the specific heat capacity of the water = 4.184 J/g⁰C.</em>
<em />
<em>Substitute the given values;</em>
45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)
4142.16 - 188.28t = 240.98
188.28t = 4142.16 - 240.98
188.28t = 3901.18
Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.
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Answer:
194 g/mol.
Explanation:
Hello,
In this case, one first must compute the mass of each element as shown below:
Next, the corresponding moles:
Then, each element's subscripts is found to be:
Therefore, the empirical formula is:
Nonetheless, it has a molar mass of 97bg/mol, thereby, by multiplying such formula by 2 one gets:
Which has a molar mass of 194 g/mol being correctly contained in the given interval.
Best regards.