Find the density of a block with a length of 8.0 cm, a width of 4.0 cm, a height 2.0 cm,

Chemistry

1 answer:

SpyIntel [72]3 years ago

4 0

Answer:

0.80 g $cm^-3$

Explanation:

$\rho=\frac{mass}{volume} \\volume= l \times w \times h = 8.0 cm \times 4.0 cm \times 2.0 cm = 64 cm^3\\\rho = \frac{51 g}{64 cm^3} =$

= 0.80 g $cm^-3$

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Solid NaI is slowly added to a solution that is 0.0079 M Cu+ and 0.0087 M Ag+.Which compound will begin to precipitate first?NaI

NeTakaya

Answer :

AgI should precipitate first.

The concentration of $Ag^+$ when CuI just begins to precipitate is, $6.64\times 10^{-7}M$

Percent of $Ag^+$ remains is, 0.0076 %

Explanation :

$K_{sp}$ for CuI is $1\times 10^{-12}$

$K_{sp}$ for AgI is $8.3\times 10^{-17}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgI has a smaller than CuI then AgI should precipitate first.

Now we have to calculate the concentration of iodide ion.

The solubility equilibrium reaction will be:

$CuI\rightleftharpoons Cu^++I^-$