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Thepotemich [5.8K]
3 years ago
6

Find the density of a block with a length of 8.0 cm, a width of 4.0 cm, a height 2.0 cm,

Chemistry
1 answer:
SpyIntel [72]3 years ago
4 0

Answer:

0.80 g cm^-3

Explanation:

\rho=\frac{mass}{volume} \\volume= l \times w \times h = 8.0 cm \times 4.0 cm \times 2.0 cm = 64 cm^3\\\rho = \frac{51 g}{64 cm^3} =

= 0.80 g cm^-3

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MakcuM [25]

Answer:

Earth's gravity is strong enough to hold onto its atmosphere and keep it from drifting into space.

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3 years ago
Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)
Reptile [31]

<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]

For the given chemical reaction:

C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]

We are given:

\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

4 0
3 years ago
construct the lewis structure of oo . draw the structure by placing atoms on the grid and connecting them with bonds. include al
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In Lewis dot structures, you draw the atom in the center and then surround the atom with its valence electrons. The Lewis structure for O is as shown in the attached diagram.

<h3>What is the Lewis structure of O ?</h3>

Lewis Structure of an atom of oxygen contains 6 electrons in the valence shell. Four valence electrons exist in lone pairs. It implies that oxygen atom must participate in two single bonds or one double bond in order to have an octet configuration.

A simplified representation of the valence shell electrons in a molecule  is called Lewis Structure. It shows how electrons are arranged around individual atoms in the molecule.

To know more about Lewis structure, refer

brainly.com/question/1525249

#SPJ4

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