Ionic compound, this is because the ions in a compound consist of a metal and a nonmetal... Or cation and anion. This means that they have opposite charges, so when they are in liquid form they allow for movement of electrify because they are free flowing. In contrast, as a solid they are tightly attracted and compacted so a charge cannot be carried through. Hope that helps!
Answer: I dont really know
Explanation:
To calculate the partial pressure, we have to calulate the total pressure first.
Total pressure = (nRT/V)SO2 + (nRT/V)CO2
n is the number of moles
R is the general gas constant = 0.0821 L.atm/K.mole
T is the temperature in Kelvin
V is the total volume
n SO2 = mass/molar mass = 5/ 32 + 16*2 = 0.078125
n CO2 = mass/molar mass = 5/14+ 16*2 = 0.1
T = 50+273 = 323K
V = 750/1000 = 0.75 liters
Total Pressure = (0.078125*0.0821*323/0.75) + (0.1*0.0821*323/0.75) = 2.7623 + 3.535 = 6.298 atm
Partial pressure = x SO2 * Total Pressure = (no. of moles of SO2 / total no. of moles) * Total pressure = (0.078125/0.078125+0.1) * 6.298 = 2.762 atm.
Answer:
Mf = MiVi / Vf
Explanation:
To obtain the answer to the question given, let us obtain the equation for the final concentration.
This can be obtained from the dilution equation as shown below :
MiVi = MfVf
Mi is the initial concentration
Mf is the final concentration
Vi is the initial volume
Vf is the final volume.
Making Mf the subject of the above equation, we can obtain the equation which can be used to calculate the final concentration. This is illustrated below:
MiVi = MfVf
Divide both side by Vf
Mf = MiVi / Vf
Therefore, the equation which can be used to calculate the final concentration is Mf = MiVi / Vf
