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iogann1982 [59]
3 years ago
9

Ammonia gas occupies a volume of 0.450 L at a pressure of 96 kPa. What

Physics
1 answer:
Sauron [17]3 years ago
6 0

Answer:

0.426 L

Explanation:

Boyles law is expressed as p1v1=p2v2 where

P1 is first pressure, v1 is first volume

P2 is second pressure, v2 is second volume.

Given information

P1=96 kPa, v1=0.45 l

P2=101.3 kpa

Unknown is v2

Making v2 the subject from Boyle's law

v2=\frac {p1v1}{p2}

Substituting the given values then

v2=\frac {96*0.45}{101.3}=0.4264560710760l\approx 0.426 l

Therefore, the volume is approximately 0.426 L

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