Ammonia gas occupies a volume of 0.450 L at a pressure of 96 kPa. What
1 answer:
Answer:
0.426 L
Explanation:
Boyles law is expressed as p1v1=p2v2 where
P1 is first pressure, v1 is first volume
P2 is second pressure, v2 is second volume.
Given information
P1=96 kPa, v1=0.45 l
P2=101.3 kpa
Unknown is v2
Making v2 the subject from Boyle's law
Substituting the given values then
Therefore, the volume is approximately 0.426 L
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Answer:
p = 22.5 cm
Explanation:
For this exercise we must use the equation of the constructor
where f is the focal length, p and q are the distance to the object and the image respectively.
Let's start with the far point, the object is very far away (p = ∞) and the image must be formed at the far point of view of the person q = 45.0 cm
since the image is on the same side as the object according to the sign convention the distance is negative
f = -45.0 cm
now let's use the near point (q = 15.0 cm) at what distance the object should be
1 / p = 1 / -45 - 1 / -15
1 / p = -1/45 + 1/15
= 0.0444
p = 22.5 cm
this is the closest distance you can see an object clearly