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anzhelika [568]
3 years ago
9

A crate of apples weighing 71.4 N sits at rest on a ramp that runs from the ground to the bed of a truck. The ramp is inclined a

t 20.0° to the ground. What is the interaction partner of normal force?
1. If the interaction partner is acting above the surface of the ramp, enter a positive value.
2. If the interaction partner is acting below the surface of the ramp, enter a negative value.
Physics
1 answer:
nika2105 [10]3 years ago
5 0

Answer:

Fint = - 67.094 N

Explanation:

Given

W = 71.4 N

∅ = 20º

Fint = ?

The interaction partner of the Normal Force has equal magnitude and opposite direction to the Normal Force, and it is a contact force exerted by the crate on the ramp, because the interaction parteners are the same force acts on the two object.

Then:    Fint = - N = - Wy' = - W*Cos ∅  

⇒   Fint = - 71.4 N*Cos 20º = - 67.094 N

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<u>Equilibrium constant</u> :The equilibrium constant comes from the chemical equilibrium law. For the chemical equilibrium state, at a fixed constant temperature, the ratio of the product of the reaction's multiplication to the concentration of its reactants' multiplication, and each is raised to the power to the corresponding coefficients of the elements in the reaction.

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