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3 years ago

Fling Find the slope of the line passing through the points (1,5) and (4,-2).

1 answer:

5 0

Subtract x2 from x1 to get -7. After that subtract y2 from y1 to receive 3. That leaves you with -7/3 which simplified is -2.1333*

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Mmmmmmmmmmmmmmmmmmhmmmmmmmmmmm

Stells [14]

Answer:

14.07

Step-by-step explanation:

first multiply x by y

5 0

3 years ago

In a soccer game, Sally kicks the ball to a teammate who is on the other side of the field. The ball's height h (in feet above t

Katena32 [7]

Answer: 0

Step-by-step explanation:

h ( t ) = − 2 t ^2 + 10 t

h = height of ball above the ground

t = time, seconds after ball was kicked

Height of ball at the time it is kicked?

At the time ball is kicked, time (t) = 0

Therefore,

h ( t ) = − 2 t ^2 + 10 t

h( 0) = - 2(0)^2 + 10(0)

h = 0 + 0

h = 0

The ball was the on the grounf at the time it was kicked.

6 0

3 years ago

What is 5 x 5 in expanded form<br>

NikAS [45]

Answer:

5×10°

Hope this helped you!!!

3 0

3 years ago

5/6 = 1/3+d and x/x is a fraction

Alik [6]

$\dfrac{1}{3}+d=\dfrac{5}{6}\qquad|-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1\cdot2}{3\cdot2}\\\\d=\dfrac{5}{6}-\dfrac{2}{6}\\\\d=\dfrac{5-2}{6}\\\\d=\dfrac{3}{6}\\\\d=\dfrac{3:3}{6:3}\\\\\boxed{d=\dfrac{1}{2}}$

7 0

3 years ago

44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access

DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.

FileSystemLocked → ∀x Access(x, SystemMailbox)

(c)

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0

3 years ago