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azamat
3 years ago
9

What is the square root of 9/100

Mathematics
1 answer:
Genrish500 [490]3 years ago
7 0

Step-by-step explanation:

<u>This number given in the above question is the square root of 3/10</u> .

First of all ,

    we can write 9 as  3²,

   and 100 can be written as 10².

  ⇒  Now when we take the root of this two  -

  ⇒   √ 3²/10²

 we get ,

   ⇒  3/10

 The square  root of 9/100 is <u>3/10</u> .

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11/6+3 is 29/6. 2/(29/6) is 12/29, which is the answer.
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g A coffee-dispensing machine is supposed to deliver eight ounces of liquid into each paper cup, but a consumer believes that th
kap26 [50]

Answer: Reject the eight- ounces claim.

Step-by-step explanation:

For left tailed test , On a normal curve the rejection area lies on the left side of the critical value.

It means that if the observed z-value is less than the critical value then it will fall into the rejection region other wise not.

As per given ,

Objective : A coffee-dispensing machine is supposed to deliver eight ounces of liquid or less.

Then ,

H_0: \mu=8\\\\H_a: \mu , since alternative hypothesis is left-tailed thus the test is an left-tailed test.

the critical value for z for a one-tailed test with the tail in the left end is -1.645 and the obtained value is -1.87.

Clearly , -1.87 < -1.645

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3 years ago
Markuo had 20 minutes to do a three-problem quiz. He spent 10 1 4 minutes on question A and 6 4 5 minutes on question B. How muc
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3 years ago
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Answer:

1) b and m

2) m∠8=m∠6

3) 160°

4)x=60°

Step-by-step explanation:

1) all straight lines sum to 180°

subtract the angles given from 180°

the other angle for b is 25°, while the other angle for m is 155°

so we can see that the angles for both lines are the same, hence they are parallel.

2) ∠8 should be the same as ∠6, ∠10 should be the same as ∠3, ∠7 same as ∠5 and ∠9 same as ∠4

in the options we are only given '∠8 should be the same as ∠6' as the correct answer, so we take that.

3) from the image we can see that both horizontal lines are parallel to each other, so both angles on the lines should be same, so ∠CET would be (2x-16)°

(2x-16)°+(7x+20)°=180°

we get x=20(nearest whole number)

∠CED=7x+20=7(20)+20=160°

4) since we need to show that they are parallel,

(2x+30)°=(4x-90)°

2x-4x=-90-30

-2x=-120

x=60

we then plug the x value into the two equations, in which we get 150° for both the angles [2(60)+30=4(60)-90] ⇒ (150=150)

I hope u understand it the way I put it.

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