If the item price is x dollars with 30% off, this item cost
![\begin{gathered} x-(0.3\cdot x)=x(1-0.3)=x\cdot0.7 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x-%280.3%5Ccdot%20x%29%3Dx%281-0.3%29%3Dx%5Ccdot0.7%20%5C%5C%20%20%5Cend%7Bgathered%7D)
where 0.3 correspond to 30%.
For instance, lets suppose that the item cost $50, then we have
![50\cdot0.7=35](https://tex.z-dn.net/?f=50%5Ccdot0.7%3D35)
that is, the item will cost $35.
Answer:
The answer to the mean is 66.4
Step-by-step explanation:
58+63+68+72+71
Answer:
whole number and a fraction
Answer:
The 95% confidence interval for the population mean daily protein intake is between 69.97g and 84.03g.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1-0.95}{2} = 0.025](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1-0.95%7D%7B2%7D%20%3D%200.025)
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 1.96](https://tex.z-dn.net/?f=z%20%3D%201.96)
Now, find M as such
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
![M = 1.96*\frac{58.6}{\sqrt{267}} = 7.03](https://tex.z-dn.net/?f=M%20%3D%201.96%2A%5Cfrac%7B58.6%7D%7B%5Csqrt%7B267%7D%7D%20%3D%207.03)
The lower end of the interval is the sample mean subtracted by M. So it is 77 - 7.03 = 69.97g.
The upper end of the interval is the sample mean added to M. So it is 77 + 7.03 = 84.03g.
The 95% confidence interval for the population mean daily protein intake is between 69.97g and 84.03g.
The answer would be 34.3. Since you are rounding to the nearest tenth, you have to look at the hundreds place which is 8. 8 rounds up so therefore, 2 rounds up and becomes 3. Hope this helps!