All categories

4 years ago

A little girl kicks a soccer ball. It goes 10 feet and comes back to her. How is this possible?

1 answer:

8 0

A classic puzzle...

She either kicked it at a wall exactly 10 foot in front of her, where the ball rebounded off the wall.

Or, she kicked the ball straight up, vertically, at a 90 degree angle, where due to the law of gravity, which states that anything that goes up must come down, when the soccer ball reaches exactly 10 feet, it falls back down.
(Note: This is nearly impossible to achieve -- exactly 10 feet.)

You might be interested in

Which type of electricity is a one-time event, caused by unbalanced charges trying to become neutral again?

arlik [135]

Answer: yes

Explanation:

7 0

3 years ago

Why would an object float in water, but sink in rubbing alcohol?

Romashka [77]

Because water is more dense than the object but rubbing alcohol is less dense than the object

6 0

3 years ago

How is gamma rays used to transfer energy?

expeople1 [14]

Gamma ray (also called gamma radiation), denoted by the lower-case Greek letter gamma, is penetrating electromagnetic radiation of a kind arising from the radioactive decay of atomic nuclei. It consists of photons in the highest observed range of photon energy.

6 0

3 years ago

If a fisherman applies a horizontal force with magnitude 47.0 NN to the box and produces an acceleration of magnitude 3.20 m/s2m

musickatia [10]

Answer:

The correct solution is "14.6875 kg".

Explanation:

Given values:

Force,

F = 47.0 N

Acceleration,

a = 3.20 m/s²

Now,

⇒ $Force=Mass\times Acceleration$

or,

⇒ $F=ma$

⇒ $47.0=m\times 3.20$

⇒ $m=\frac{47.0}{3.20}$

⇒ $=14.6875 \ kg$

4 0

2 years ago

Desperate for help! please!!!!!!!!

lys-0071 [83]

$0.4029 \mathrm{m} / \mathrm{s}^{2}$ is the acceleration of the box.

Explanation:

Given data:

Mass of the box = 3.74 kg

Flat friction-less ground is pulled forward by a 4.20 N force at a 50.0 degree angle and pulled back by a 2.25 N force at a 122 degree angle.

First, we need to find the net horizontal force acting on the box. With the given data, the equation can be formed as below. Net horizontal force acting on the box (F) is given by

$F=\left(4.20 \times \cos 50^{\circ}\right)+\left(2.25 \times \cos 122^{\circ}\right)$

$F=(4.20 \times 0.64278)+(2.25 \times-0.5299)$

F = 2.699676 – 1.192275 = 1.507 N

Next, find acceleration of the box using Newton's second law of motion. This states that the link between mass (m) of an objects and the force (F) required to accelerate it. The equation can be given as

$F=m \times acceleration\ (a)$

$\text {acceleration }(a)=\frac{F}{m}=\frac{1.507}{3.74}=0.4029 \mathrm{m} / \mathrm{s}^{2}$

8 0

3 years ago