The given velocity is 465 m/s.
Part a.

Answer: 1674 km/h
Part b.

Answer: 40,176 km/day.
Answer:
7.1 Hz
Explanation:
In a generator, the maximum induced emf is given by

where
N is the number of turns in the coil
A is the area of the coil
B is the magnetic field strength
f is the frequency
In this problem, we have
N = 200


B = 0.030 T
So we can re-arrange the equation to find the frequency of the generator:

Hello,
Here is your answer:
The proper answer to this question is option B "<span>chemical properties".
Here is how:
</span>Electrons determine a atoms chemical properties mainly what its made of.
Your answer is B.
If you need anymore help feel free to ask me!
Hope this helps!
I believe it she should use the first aid kit next