Answer:
0.352M
Explanation:
First, we need to write a balanced equation for the reaction between perchloric acid and lithium hydroxide. This is shown below:
HClO4 + LiOH —> LiClO4 + H2O
From the balanced equation above, we obtained:
nA (mole of the acid) = 1
nB (mole of the base) = 1
Data obtained from the question include:
Va (volume of the acid) = 100mL
Ca (concentration of the acid) =?
Vb (volume of the base) = 46.9 mL
Cb (concentration of the base) = 0.75M
Using CaVa/CbVb = nA/nB, the concentration of the acid can obtained as follow:
CaVa/CbVb = nA/nB
Ca x 100 / 0.75 x 46.9 = 1
Cross multiply to express in linear form
Ca x 100 = 0.75 x 46.9
Divide both side by 100
Ca = (0.75 x 46.9) /100
Ca = 0.352M
Therefore the concentration of the acid is 0.352M
