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erik [133]
3 years ago
8

Solid sodium reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of hydrogen gas

are formed when (46.3 g) 48.7 g of sodium are added to water? Show your work. Assume the sodium is limiting:
Na (s) + H2O (l) H2 (g) + NaOH (s)
Also if sodium is the limiting reactant, what does this indicate about H2O in this reaction?
Chemistry
1 answer:
IrinaK [193]3 years ago
7 0
<span>convert grams to moles then use the equatino to do moles of Na to moles of H2O then convert moles of H2O to molecules by using avogadros number (6.022e23)

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
</span>
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Answer: 0.87 g of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel.

Explanation:

According to the dilution law,

C_1w_1+C_2w_2=C_3w_3

where,

C_1 = concentration of ist progesterone gel = 8%w/w

w_1 = weight of ist progesterone gel  = x g

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8\times x+4\times 1.45=5.5\times (x+1.45)

x=0.87

Thus 0.87 g of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel.

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