slope = rise over run = y/x
A (-1,3) slope = 3/-1 = -3
B (1,2) slope = 2/1 = 2
C (-3,-1) slope = -1/-3 = 1/3
2 lines need to be negative reciprocals in order to be a right triangle
negative reciprocal of -3 is 1/3
so this is a right triangle
Use the formula:
y2-y1
———
x2-x1
So for this problem it would be:
6-5
——
7-4
= 1
—
3
Hope this helped, if it did I would appreciate it if you would consider giving me brainliest!
Answer:
Step-by-step explanation:
4. f(x) = √(x + 4)
f(5) = √(5+4) = √(9) = 3
5. g(x) = x^12 - x^5
g(-1)= (-1)^12 - (-1)^5
1 - (-1) = 1 + 1 = 2
14a^2bc^4/21abc^6 = 2a/3b^2
