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Charra [1.4K]
3 years ago
14

What best explains the cause of strong winds on a island?​

Chemistry
2 answers:
n200080 [17]3 years ago
8 0
Lack of objects that could be used to slow down the winds, I.e. lack of trees or other natural barriers
Bingel [31]3 years ago
6 0
You can search this on the internet
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SOMEONE HELP PLEASE !!
aev [14]

salt is not because it gets u dehydrated

6 0
3 years ago
For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici
Brut [27]

<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

              E=E_{0}-0.0514 \mathrm{V} \ln \gamma

As we know that E_{0} = 0.22 V and E = 0.342 V, the equation will become

             0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma

             0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)

             0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)

             \frac{0.12}{0.0514}=-\ln (0.124 \gamma)

             -2.3346=\ln (0.124 \gamma)

             e^{-2.3346}=0.124 \gamma

             0.0968=0.124 \gamma

             \gamma=\frac{0.0968}{0.124}=0.78

So, the mean activity coefficient is 0.78.

6 0
3 years ago
What is the term used to describe why urban areas are warmer than surrounding rural areas?
4vir4ik [10]

Answer:

urban heat island

Explanation:

occurs when a city experiences much warmer temperatures than nearby rural areas.

Mark me brainliest.

5 0
2 years ago
The amount of matter in a object is referred as:
mestny [16]
Volume is the thing
…………….
4 0
3 years ago
Five ?L of a 10-to-1 dilution of a sample were added to 5mL of Bradford reagent. The absorbance at 595 nm was 0.78 and,according
Tomtit [17]

Answer:

0.03g/mL

Explanation:

Given parameters include:

Five μL of a 10-to-1 dilution of a sample; This implies the Volume of dilute sample is given as 5 μL

Dilution factor = 10-to-1

The absorbance at 595 nm was 0.78

Mass of the diluted sample = 0.015 mg

We need to first determine the concentration of the diluted sample which is required in calculating the protein concentration of the original solution.

So, to determine the concentration of the diluted sample, we have:

concentration of diluted sample = \frac{mass}{volume}

= \frac{0.015 mg}{ 5 \alpha L}   (where ∝ was use in place of μ in the expressed fraction)

= 0.003 mg/μL

The dilution of the sample is from 10-to-1 indicating that the original concentration is ten times higher; as such the protein concentration of the original solution can be calculated as:

protein concentration of the original solution = 10 × concentration of the diluted sample.

= 10  × 0.003 mg/μL

= 0.03 mg/μL

= \frac{0.03*10^{-3g}}{10^{-3}mL}

= 0.03g/mL

Hence, the protein concentration of the original solution is known to be  0.03g/mL

8 0
3 years ago
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