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Naddika [18.5K]
3 years ago
6

Which equation should you use to find the final concentration?

Chemistry
1 answer:
Anon25 [30]3 years ago
6 0

Answer:

Mf = MiVi / Vf

Explanation:

To obtain the answer to the question given, let us obtain the equation for the final concentration.

This can be obtained from the dilution equation as shown below :

MiVi = MfVf

Mi is the initial concentration

Mf is the final concentration

Vi is the initial volume

Vf is the final volume.

Making Mf the subject of the above equation, we can obtain the equation which can be used to calculate the final concentration. This is illustrated below:

MiVi = MfVf

Divide both side by Vf

Mf = MiVi / Vf

Therefore, the equation which can be used to calculate the final concentration is Mf = MiVi / Vf

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Propylethylene would be the answer

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Số oxi hoá của nitơ trong NH3, H2SO4, NO3 lần lượt là:
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The rate of disappearance of HBr in the gas phase reaction2HBr(g) → H2(g) + Br2(g)is 0.301 M s-1 at 150°C. The rate of appearanc
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Answer: 0.151

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2HBr(g)\rightarrow H_2(g)+Br_2(g

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{1d[HBr]}{2dt}=+\frac{1d[H_2]}{2dt}=+\frac{1d[Br_2]}{dt}

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Putting in the values we get:

\frac{0.301}{2}=+\frac{1d[Br_2]}{dt}

+\frac{1d[Br_2]}{dt}=0.151

Thus the rate of appearance of Br_2 is 0.151

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3 years ago
Which of the following months would be the darkest at the South Pole?
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3 years ago
135 grams of sodium has ______ moles.<br><br> (Enter just the number for this one.)
just olya [345]

Answer : 135 grams of sodium has 5.869 moles.

Solution : Given,

Mass of sodium = 135 grams

Molar mass of sodium = 23 g/mole

Formula used :

\text{Moles of sodium}=\frac{\text{Mass of sodium}}{\text{Molar mass of sodium}}

Now put all the given values in this formula, we get

\text{Moles of sodium}=\frac{135g}{23g/mole}=5.869moles

Therefore, the moles of sodium present in 135 grams of sodium is, 5.869 moles.


6 0
3 years ago
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