The chemical reaction is expressed as:
<span> 4KO2+2CO2→2K2CO3+3O2
</span>
We are given the amount of KO2 to be used in the reaction. This will be the starting point of our calculations. We do as follows:
0.425 mol KO2 ( 3 mol O2 / 4 mol KO2 ) = 0.319 mol O2 produced
Hope this answers the question. Have a nice day.
The answer to your questions is as follows:
most soluble
>CH3CH2OH
>CH3OCH3
>CH3CH3
<span>least soluble
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Three classes: 28×3=84 students
8 test tubes per student: 84× 8= 672
hope this helps!
