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2 years ago

You can prepare a buffer solution by combining equal moles of which pair of substances?

Chemistry

1 answer:

zzz [600]2 years ago

8 0

Answer:

A. weak acid and its conjugate base

Explanation:

A buffer solution can be made with a weak acid and conjugate base or a weak base and conjugate acid.

This may help you:

https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Acids_and_Bases/Buffers/Introduction_to_Buffers

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Convert 65.4 m to mm.<br> Helppp please

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Answer:65.4 meters= 65400 millimeters

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2 years ago

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Give three examples of environmental, industrial and bio-chemistry.

JulsSmile [24]

Three examples of environmental, industrial and bio-chemistry are listed below:

Environmental chemistry: Contamination, Atmospheric Deposition, and Soil Pollution.
industrial chemistry: industrial inorganic chemicals, industrial organic chemicals, and agricultural chemicals
bio-chemistry: genetic, immunology, and enzymology

<h3>Meaning of Chemistry</h3>

Chemistry can be defined as a branch of science which is concerned with the substances matter is composed of, their properties and reactions,

Chemistry also deals with the use of such reactions to form new substances.

In conclusion, Three examples of environmental, industrial and bio-chemistry are listed anove

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1 year ago

Balance the equation for the reaction in which sodium oxide reacts with water to form sodium hydroxide.

tensa zangetsu [6.8K]

Answer:

$➢ \: Balance \: the \: equation \: for \: the \: reaction \\ in \: which \: sodium \: oxide \: reacts \\ with \: water \: to \: form \: sodium \: hydroxide.$

⇒ We have Na2O + H2O --> NaOH. We have 2 sodiums and 2 oxygens and 2 hydrogens on the left side, but only one of each on the right side.

Sodium Oxide + Water → Sodium Hydroxide

⇒ Na2O + H2O → 2NaOH .

Sodium oxide is used in ceramics and glasses. Sodium oxide reacts exothermically with cold water to produce sodium hydroxide solution.

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1 year ago

Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th

WINSTONCH [101]

<u>Answer:</u> The standard enthalpy change of the reaction is coming out to be -16.3 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]$

We are given:

$\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ$

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

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3 years ago

In which of the following are photosynthesis and resperation alike

tresset_1 [31]

Answer:

i need a picture or more info to understand

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2 years ago

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