Percent yield is 23.11 % when 162.8 g of CO2 are formed from the reaction of excess amount of C8H18 and with 218.0 grams of O2.
Explanation:
Balanced equation for the chemical reaction:
2C8H18 + 25O2 → 16CO2 + 18H2O
data given:
CO2 formed (actual yield) = 162.8 grams
mass of oxygen = 218 grams
16 moles of CO2 formed when 5 moles of oxygen reacted
3.6 moles of CO2 formed when 6.8 moles of oxygen reacted.
In the reaction 16 moles of CO2 will have 44.01 x 16
theoretical yield of CO2 = 704.16 grams
percent yield = 
x100
putting the values in the above equation
percent yield = 
x 100
= 0.23 x 100
= 23.11 %
Percent yield is 23.11 %.
Answer:
The molality of the glycerol solution is 2.960×10^-2 mol/kg
Explanation:
Number of moles of glycerol = Molarity × volume of solution = 2.950×10^-2 M × 1 L = 2.950×10^-2 moles
Mass of water = density × volume = 0.9982 g/mL × 998.7 mL = 996.90 g = 996.90/1000 = 0.9969 kg
Molality = number of moles of glycerol/mass of water in kg = 2.950×10^-2/0.9969 = 2.960×10^-2 mol/kg
Answer:
158.2598
Explanation:
158.2598 moles are in 78.8 g of potassium sulfite
CARRY ON LEARNING
Answer:
about 327 g of sulfur
Explanation:
Reaction equations.
2S + 2O2 = 2SO2
2SO2 + O2 = 2SO3
2SO3 + 2H2O = 2H2SO4
1.00 kg H2SO4 (1000 g H2SO4 / 1kg H2SO4) x (1 mole H2SO4 / 98.079 g H2SO4) x
(1 mole S / 1 mole H2SO4) x (32.065 g S / 1 mole S)
= 326.93 g S needed to be burned to produce 1.00 kg of H2SO4
Answer:
Ions
Explanation:
Ionic bonds are formed when an element loses electrons (usually a metal), and other elements gain these electrons(usually a nonmetal or the hydrogen). When the element loses electrons, it becomes a cation, an ion with a positive charge; and when the element gains electrons it becomes an anion, an ion with a negative charge.
The charge in the ions produces an electrostatic attraction between them, and that attraction is the force that gets them together in a bond.
